Empirical formula is the simplest ratio of whole numbers of components in a compound.
Assuming for 100 g of the compound
Cu As S
mass 48.41 g 19.02 g 32.57 g
number of moles 48.41 / 63.5 g/mol 19.02 / 75 g/mol 32.57 / 32 g/mol
= 0.762 mol = 0.2536 mol = 1.018 mol
divide by the least number of moles
0.762 / 0.2536 0.2536 / 0.2536 1.018 / 0.2536
= 3.00 = 1.00 = 4.01
once they are rounded off
Cu - 3
As - 1
S - 4
therefore empirical formula is Cu₃AsS₄
To convert the given value we need conversion factors to relate molecules to liters. At STP, we know that 1 mol is equal to 22.4 L and by using Avogadro's number we can relate molecules to 1 mol. Calculation is as follows:
5.0x10^24 molecules ( 1
mol / <span>6.022 x 10^23 molecules<span> ) ( 22.4 L / 1 mol) = 186.0 L </span></span>
Answer:physical: a part falling off or changing a tire. chemical:rust
Explanation:
Answer:
C₆H₆
Explanation:
Molar mass of the compound is 78g/mol
Unknown:
Molecular formula of the compound = ?
Solution:
The empirical formula of the compound is CH.
Empirical formula is the simplest formula of a compound.
To solve this problem:
Find the molar mass of CH;
Molar mass = 12 + 1 = 13g/mol
Multiplication index = 
= 6
So;
(CH)₆ ;
Therefore:
C₆H₆
