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Bezzdna [24]
3 years ago
6

. If this same atom with 22 protons and 19 electrons were to gain 3 electrons, the net charge on the atom would be

Chemistry
1 answer:
mina [271]3 years ago
3 0

Answer:

neutral

Explanation:

19+3=22

22 protons & 22 neutrons --> neutral net charge

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Examine the equation.
Alisiya [41]

Explanation:

The reaction expression is given as;

                 2H₂_{g}   +  O₂_{g}   →   2H₂O_{l}

From the balance reaction expression:

 2 mole of hydrogen gas combines with 1 mole of oxygen gas on the reactant side;

This produces 2 mole of water on the product side of the expression.

The product is in liquid form.

 This reaction is a synthesis reaction because a single product is formed from two reactants.

5 0
3 years ago
Pure water is an electrolytic solution. <br><br><br> True <br> False
dmitriy555 [2]
The answer to this is false. 
6 0
4 years ago
You have a solid 7.00 gram mixture of sodium nitrate and silver nitrate. You add distilled water to dissolve the solids. Now you
olganol [36]

Answer:

Net ionic equation: Ag⁺(aq) + Cl⁻(aq) → AgCl(s)

44.9% as AgNO₃

Explanation:

When sodium nitrate, NaNO₃ and silver nitrate, AgNO₃ are dissolved in water, the Na⁺, NO₃⁻ and Ag⁺ ions are formed.

Then, the addition of NaCl (Na⁺ and Cl⁻) produce AgCl⁻ as precipitate. <em>The net ionic equation is:</em>

<h3>Ag⁺(aq) + Cl⁻(aq) → AgCl(s)</h3><h3 />

If 2.54g of AgCl are formed and represents the 95.9% of yield. The real amount of AgCl is:

2.54g AgCl * (100% / 95.9%) = 2.65g AgCl.

In moles (Molar mass AgCl = 143.32g/mol):

2.65g AgCl * (1mol / 143.32g) = 0.0185 moles of AgCl = Moles of AgNO₃

<em>Because all Ag comes from AgNO₃</em>

<em />

Thus, the original mass of silver nitrate and its precentage is (Molar mass AgNO₃ = 169.87g/mol):

0.0185 moles AgNO₃ * (169.87g / mol) = 3.14g of AgNO₃

Percentage:

3.14g AgNO₃ / 7.00g * 100 =  

<h3>44.9% as AgNO₃</h3>
3 0
3 years ago
Silver sulfate (Ag2SO4) is slightly soluble in water and it partly dissolves at the equilibrium according to the following balan
statuscvo [17]

Answer:

a) S = 0.0152 mol/L

b) S' = 4.734 g/L

Explanation:

  • Ag2SO4 ↔ 2Ag+  +  SO42-

           S                2S            S...............in the equilibrium

  • Ksp = 1.4 E-5 = [ Ag+ ]² * [ SO42-]

a) molar solubility:

⇒ Ksp = ( 2S) ² * S = 1.4 E-5

⇒ 4S² * S = 1.4 E-5

⇒ S = ∛ ( 1.4 E-5 / 4 )

⇒ S = 0.0152 mol/L

b) solubility ( S' ) in grams per liter:

∴ Mw Ag2SO4 = 311.799 g/mol

⇒ S' = 0.0152 mol/L * ( 311.799 g/mol )

⇒ S' = 4.734 g/L

3 0
3 years ago
A chef is testing out a new set of iron cookware. He knows that iron has a specific heat of 445 J/kg°C. He heats a 2 kg iron ski
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Answer:

yo whats good nebyu its nathan Imao

Explanation:

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