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3 years ago

How can positive feedback influence the stability of a system?

Physics

2 answers:

son4ous [18]3 years ago

8 0

Answer: it's b

Explanation: I did it already

SVEN [57.7K]3 years ago

3 0

Answer:

Explanation:

Apex

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(a) What is the vapor pressure of water at 20.0ºC ? (b) What percentage of atmospheric pressure does this correspond to? (c) Wha

DENIUS [597]

Answer:

a). Vapour pressure = 2333.141 Pa

b). Percentage of atmospheric pressure = 99 %

c). Percentage of water vapour = 1.4 %

Explanation:

a). From water saturation pressure table,

Vapour pressure of water at 20°C is 17.5 torr

We know, 1 torr = 133.322 Pa

Therefore, 17.5 torr = 2333.141 Pa

Therefore, vapour pressure at 20°C is 2333.141 Pa

b). At 20°C, the pressure at atmospheric unit = 0.0231 atm

= 0.0231 x $10^{5}$ Pa

= 2310 Pa

Therefore, $\frac{2310}{2333.141}$

= 0.99

Therefore percentage of atmospheric pressure = 0.99 x 100

= 99 %

c). We Know

Relative Humidity (Rh)= $\frac{P_{v}}{P_{saturation}}$

where $P_{v}$ is vapour pressure

Rh is given as 100% = 1

∴ 1 = $\frac{P_{v}}{P_{saturation}}$

$P_{v}=P_{saturation}$ = 2333.141 Pa

Now humidity ratio is

$w = \frac{m_{v}}{m_{a}}$ , where $m_{v}$ is mass of vapour

$m_{a}$ is mass of air

$w = 0.622\times \frac{P_{v}}{P_{total}-P_{v}}$

Let the total pressure be $10^{5}$ Pa

$w = 0.622\times \frac{2333.141}{10^{5}-2333.141}$

$w = 0.01485$

Therefore, percentage of water vapour is 0.01485 x 100

= 1.4 %

8 0

3 years ago

A parallel-plate capacitor is connected to a battery. The space between the two plates is empty. If the separation between the c

Maru [420]

Answer:

The final stored energy will become half.

Explanation:

We know that stored energy in the capacitor is given as

$E=\dfrac{1}{2}CV^2$

C=capacitance

V=Voltage difference

E=Energy

$C=\dfrac{\varepsilon A}{d}$

d=Distance between plates

A=Area

$E=\dfrac{1}{2}\times \dfrac{\varepsilon A}{d}\times V^2$

If the distance between plates get double ,say d' = 2 d

Then stored energy

$E'=\dfrac{1}{2}\times \dfrac{\varepsilon A}{d'}\times V^2$

$E'=\dfrac{1}{2}\times \dfrac{\varepsilon A}{2d}\times V^2$

$E'=\dfrac {E}{2}$

Therefore the final stored energy will become half.

5 0

4 years ago

A 5200w electric oven

OLga [1]

Answer:

104 kWh

Explanation:

To calculate the kWh you multiply power with the amount of hours.

So for this we take 5200 W × 20 = 104 000 Wh

Then change Wh to kWh so that makes 104 kWh

8 0

2 years ago

A tugboat pulls a ship with a constant net horizontal force of 5.00 x 10 to the 3 power n and causes the ships to move through a

Mashutka [201]

Work is force times distance. So here we have
W=(5000N)x(3000m)=1.5x10^7J
Or 15MJ (megajoules)

5 0

3 years ago

What is the minimum body mass index for obesity

Tju [1.3M]

Overweight:25 to 30, obese: over 30

3 0

3 years ago

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