The efficiency of the scissor is 200%.
<u>Explanation:</u>
Efficiency is defined as the ratio of output of any instrument or device or machine to the input supplied to it. So the greater the output the greater will be the efficiency of the device.
As here the work done by us on the system is said to be 10 J so this will be equal to the input work done on the system. And the work done by the system i.e., the scissor is 20 J, so this will be the output work.
So, the efficiency is the ratio of output to input as shown below.
Efficiency = 
= 200
So, the efficiency of the scissor is 200%.
Well if you're experiencing severe pain obviously you can tell its broken
Answer:
1) x_total = 2.7 km=2700 m, 2) t_total = 1926 s, 3) v_avg = 1.40 m / s
Explanation:
1) To solve this uniform velocity problem, we must find the displacement of each part and add them.
x_total = x₁ + x₂
x_total = 0.7 + 2.0
x_total = 2.7 km
2) how long does it take for this tour
truck
v = x₁ / t₁
t₁ = x₁ / v
t₁ = 0.7 / 20
t₁ = 0.035 h
Let's reduce the time to the SI system
t₁ = 0.035 h (3600 s / 1h) = 126 s
when he is walking
t₂ = 30 min (60 s / 1min) = 1800 s
the total time is
t_total = t₁ + t₂
t_total = 126 + 1800
t_total = 1926 s
3) the average velocity is defined as the displacement in the inerval between time
v_avg = x_total / t_total
v_avg = 2700/1926
v_avg = 1.40 m / s
