Momentum = mv
where m is the mass of an electron and v is the velocity of the electron.
v = momentum ÷ m
= (1.05×10∧-24)÷(9.1×10∧-31) = 1,153,846.154 m/s
kinetic energy = (mv∧2)÷2
= (9.1×10∧-31 × 1,153,846.154∧2) ÷2
= (1.21154×10∧-18) ÷ 2
= 6.05769×10∧-19 J
Answer:
x-component=-9.3 m
Magnitude of A=17.7m
Explanation:
We are given that


We have to find the x-component of A and magnitude of A.
According to question

Substitute the values then we get


m




The value of x-component of A is negative because the vector A lie in second quadrant.
Hence, the x- component of A=-9.3 m
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,
KE1 = KE2
The kinetic energy of the system before the collision is solved below.
KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
KE1 = 6125 g cm²/s²
This value should also be equal to KE2, which can be calculated using the conditions after the collision.
KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)
The value of x from the equation is 17.16 cm/s.
Hence, the answer is 17.16 cm/s.
Hello,
Here is your answer:
The proper answer to this question is option B "<span>chemical properties".
Here is how:
</span>Electrons determine a atoms chemical properties mainly what its made of.
Your answer is B.
If you need anymore help feel free to ask me!
Hope this helps!