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Wittaler [7]
3 years ago
10

B. Find the centripetal force needed to keep an 60.0 kg rider traveling in a circle in the ride.

Physics
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

loloololo

lol

Explanation:

lolloolololo

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How does lemon produce electricity
oksian1 [2.3K]

Answer:

Below!

Explanation:

The citric acid in the lemon acts as an electrolyte, a solution that conducts electricity. The zinc nail sheds electrons as electrically charged ions into the acid (a process called “Oxidation” because the material loses electrons). ... The average lemon output is . 9 volts at .

5 0
2 years ago
In both a dry cell and a wet cell battery, what causes the production of an electrical current.
koban [17]

Answer:

a. chemical reaction

Explanation:

In both a dry and wet cell battery, electric currents are produced through chemical reactions.

Both cells are together called electrochemical cells.

  • In these cells, chemical reactions produce an electric current.
  • They are devices that converts chemical energy into electrical energy
  • The reactions here are spontaneous redox reactions.
  • This causes the current to flow on their own in the circuit.
4 0
3 years ago
A 1.00 kg object moving in the + x direction at 10.0 m/s collides with a 1.50 kg object traveling at 5.00 m/s in the - x directi
marysya [2.9K]

Answer:

The amount of kinetic energy lost during the collision is 60.75 J

Explanation:

The given parameters are;

The mass of the object moving in the +x direction, m₁ = 1.00 kg

The velocity of the object moving in the +x direction, v₁ = 10.0 m/s

The mass of the object moving in the -x direction, m₂ = 1.50 kg

The velocity of the object moving in the +x direction, v₂ = 5.00 m/s

The final velocity of the 1.00 kg mass after collision, v₃ = 4.00 m/s

The direction of motion of the 1.00 kg mass after collision = -x direction

The total initial kinetic energy of the system, K.E._{total \ initial} = 1/2·m₁·v₁² + 1/2·m₂·v₂²

∴ K.E._{total \ initial}  = 1/2×1.00×10² + 1/2×1.50×5² = 68.75 J

The final kinetic energy of the system, K.E._{final}  = 1/2·m₁·v₃²

K.E._{final} = 1/2×1.00×4² = 8 J

The amount of kinetic energy lost during the collision, \Delta K.E._{system} is given as follows;

\Delta K.E._{system} =  K.E._{final} -K.E._{total \ initial} = 8 J - 68.75 J = -60.75 J

The amount of kinetic energy lost during the collision = 60.75 J.

7 0
3 years ago
Two ropes are attached to a 40-kg object. The first rope applies a force of 50 N and the second, 40 N. If the two ropes are perp
Montano1993 [528]

To solve this problem we will use the concepts related to the resulting Vector Force product of two components, that is,

|\vec{F}| = \sqrt{F_x^2+F_y^2}

If we take the Force of 50 N as the force in the X direction and the Force of 40 N in the Y direction we will have to:

|\vec{F}| = \sqrt{F_x^2+F_y^2}

|\vec{F}| = \sqrt{(50)^2+(40)^2}

|\vec{F}| = 64.03N

Finally, since Newton's second law, acceleration can be determined as

F = ma

a = \frac{F}{m}

a = \frac{ 64.03}{40}

a = 1.6m/s^2

Therefore the resultant magnitude of the acceleration of the object is 1.6m/s^2

4 0
3 years ago
When the ambulance passes the person (switching from moving towards him to moving away from him), the perceived frequency of the
dlinn [17]

To develop this problem we will apply the considerations made through the concept of Doppler effect. The Doppler effect is the change in the perceived frequency of any wave movement when the emitter, or focus of waves, and the receiver, or observer, move relative to each other. At first the source is moving towards the observer. Than the perceived frequency at first

F_1 = F \frac{{343}}{(343-V)}

Where F is the actual frequency and v is the velocity of the ambulance

Now the source is moving away from the observer.

F_2 = F\frac{343}{(343+V)}

We are also so told the perceived frequency decreases by 11.9%

F_2 = F_1 - 9.27\% \text{ of } F_1

F_2 = F_1-0.0927F_1

F_2 = 0.9073F_1

Equating,

F\frac{343}{(343+V)}= 0.9073(F\frac{343}{(343-V)})

\frac{1}{(343+V)}= 0.9073\frac{1}{(343-V)}

0.9073(343+V) = 343-V

(0.9073)(343)+(0.9073)V = 343-V

V+0.9073V = 343-(0.9073)(343)

Solving for V,

V = 16.67 m/s

5 0
3 years ago
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