Answer:
Vertical Height = 0.784 meter, Speed back at starting point = 10 m/s
Explanation:
Given Data:
V is the overall velocity vector,
and
are its initial vertical and horizontal components
![R = 10 m/s\\ Projection Angle (theta) = 30 degrees\\Vi = 10*sin(30) = 5 m/s\\Ui = 10*cos(30) = 8.66 m/s](https://tex.z-dn.net/?f=R%20%3D%2010%20m%2Fs%5C%5C%20Projection%20Angle%20%28theta%29%20%3D%2030%20degrees%5C%5CVi%20%20%20%3D%2010%2Asin%2830%29%20%3D%205%20m%2Fs%5C%5CUi%20%20%3D%2010%2Acos%2830%29%20%3D%208.66%20m%2Fs)
To find:
Max Height
achieved
Calculation:
1) Using the
equation of motion, we know
![2*a*s = Vf^{2} - Vi^{2}](https://tex.z-dn.net/?f=2%2Aa%2As%20%3D%20Vf%5E%7B2%7D%20%20-%20Vi%5E%7B2%7D)
2) In terms of gravity
height
and the vertical component of Velocity
.
3) As
as at maximum height the vertical component of velocity is zero maximum height achieved
![2*g*h = Vf^{2} -Vi^{2}](https://tex.z-dn.net/?f=2%2Ag%2Ah%20%3D%20Vf%5E%7B2%7D%20%20-Vi%5E%7B2%7D)
putting values
4) ![h = 0.784 m/s](https://tex.z-dn.net/?f=h%20%3D%200.784%20m%2Fs)
5) As for the speed when it reaches back its starting point, it will have a speed similar to its launching speed, the reason being the absence of air friction (Air drag)
Answer:
The correct answer is option ( D ) Yoga
Explanation:
hope it helps you dear :)
have a nice day
You are asked to give the answer in <span>g/cm3. So without knowing any single formulae you can just divide grams by cm3.
</span>
![\frac{99 grams}{22 cm^{3} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B99%20grams%7D%7B22%20cm%5E%7B3%7D%20%7D%20)
= 4.5 g/cm3
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