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LenKa [72]
4 years ago
8

What is denser a iron sheet or iron powder??

Physics
1 answer:
Ainat [17]4 years ago
7 0
Iron sheet because the molecules are more condense.
I guess Im Not sure
You might be interested in
QuestIuI
WARRIOR [948]

Given Information:

Mass of elephant = m = 750 kg

Height = h = 14.3 m  

time = t = 30 seconds

Required Information:

Power needed to lift elephant = P = ?

Answer:

Power needed to lift elephant ≈ 3507 watts

Explanation:

As we know power is given by

P = PE/t

Where PE is the potential energy and t is the time

Potential energy is given by

PE = mgh

Where m is the mass of elephant, g is the gravitational acceleration and h is the height to lift the elephant.

PE = 750*9.81*14.3

PE = 105212.25 Joules

Therefore, the required power to lift the elephant is

P = PE/t

P = 105212.25/30

P ≈ 3507 watts

8 0
4 years ago
A playground carousel is rotating counterclockwise about its center on frictionless bearings. A person standing still on the gro
Shtirlitz [24]

Answer:

1.94601 rad/s

Explanation:

I_1 = Moment of inertia of carousel = 124 kgm²

\omega_1 = Angular speed of carousel = 3.5 rad/s

\omega_2 = Angular speed of person

r = Radius of carousel = 1.53 m

m = Mass of person = 42.3 kg

Moment of inertia of person

I_2=mr^2\\\Rightarrow I_2=42.3\times 1.53^2\\\Rightarrow I_2=99.02007\ kgm^2

As the angular momentum is conserved in the system

I_1\omega_1=(I_1+I_2)\omega_2\\\Rightarrow \omega=\frac{I_1\omega_1}{(I_1+I_2)}\\\Rightarrow \omega_2=\frac{124\times 3.5}{(124+99.02007)}\\\Rightarrow \omega_2=1.94601\ rad/s

The angular speed of the carousel after the person climbs aboard is 1.94601 rad/s

5 0
3 years ago
A small ball with a mass of 0.6 kg and a velocity of 12 m/s hits another ball with the same mass. The firs forward and hits a th
Ket [755]
I think is 30m/s I am not sure
8 0
3 years ago
At which position would a person on Earth be able to view a solar eclipse?<br> A<br> B<br> C<br> D
sweet-ann [11.9K]
The answer would be A, since at that position the Earth is fully/partially being engulfed in a shadow cast by the moon from the sun’s rays.

Hope this helps!
5 0
3 years ago
Đun nóng đẳng áp 5 kmol khí, người ta đã truyền cho khí một nhiệt lượng 9,4.10^6 J và khi đó khí đã nóng thêm 400K. Tính công mà
gulaghasi [49]

Explanation:

Hi Linda,

How's it going?

Sorry I haven't been in touch for such a long time but I've had exams so I've been studying every free minute. Anyway, I'd love to hear all your news and I'm hoping we can get together soon to catch up. We just moved to a bigger flat so maybe you can come and visit one weekend?

How's the new job?

Looking forward to hearing from you!

Helga

6 0
3 years ago
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