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Reptile [31]
3 years ago
14

What is the molarity of a solution that contains 40. grams of NaOH in 0.50 liter of solution

Chemistry
1 answer:
statuscvo [17]3 years ago
5 0

Answer:

The molarity of the solution is: 2 M

Explanation:

We calculate the weight of 1 mol of NaOH:

Weight 1 mol NaOH= Weight Na + Weight 0 + Weight H= 23 g+16g+ 1 g= 40g/mol

The molarity is the quantity of moles in 1000ml (1 liter) of solution:

0,5liter-----40 grams NaOH

1 liter----x=(1 liter x 40 grams NOH)/0,5 liter = 80 grams NaOH

40 grams----1 mol NaOH

80 grams----X=(80 grams x 1 mol NaOH)/40 grams= 2 mol NaOH--> 2M

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Ierofanga [76]
Ion solution is correct. hope it helps
6 0
3 years ago
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14. What volume (mL) of water do I need to add to 425
Reptile [31]

Answer:

212.5 mL

both the original and the diluted solution have 0.765 moles of KCl

Explanation:

c1V1 = c2V2

V2 = c1V1/c2 = (1.8 M×425 mL)/1.2 M = 637.5 mL

(637.5 - 425) mL = 212.5 mL

n = (1.8 mol/L)(0.425 L) = 0.765 moles of KCl

since it's a dilution, the diluted solution has the same number of moles as the original solution, 0.765 moles of KCl

7 0
2 years ago
In the following reaction, what is the effect on the direction of the reaction if more SO3 is added to the reaction mixture?
Stolb23 [73]

Answer:

The equilibrium shifts to produce more reactants.

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

Consider the following chemical reaction.

Chemical reaction:

2SO₂ +  O₂  ⇄  2SO₃

In this reaction the equilibrium is disturb by increasing the concentration of Product.

When the concentration of product is increased the system will proceed in backward direction in order to regain the equilibrium. Because when product concentration is high it means reaction is not on equilibrium state. As the concentration of SO₃  increased the reaction proceed in backward direction to regain the equilibrium state and more reactant is formed.

3 0
2 years ago
The one factor that a scientist changes in an experiment is called the
Gala2k [10]

Answer:

It might be responding variable.

8 0
3 years ago
Automobile airbags contain solid sodium azide, NaN3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2N
Vitek1552 [10]

Answer : The value of work done for the system is 1144.69 J

Explanation :

First we have to calculate the moles of NaN_3

\text{Moles of }NaN_3=\frac{\text{Mass of }NaN_3}{\text{Molar mass of }NaN_3}

Molar mass of NaN_3 = 65.01 g/mole

\text{Moles of }NaN_3=\frac{20.2g}{65.01g/mole}=0.311mole

Now we have to calculate the moles of nitrogen gas.

The balanced chemical reaction is,

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

From the balanced reaction we conclude that

As, 2 mole of NaN_3 react to give 3 mole of N_2

So, 0.311 moles of NaN_3 react to give \frac{0.311}{2}\times 3=0.466 moles of N_2

Now we have to calculate the volume of nitrogen gas.

Using ideal gas equation:

PV=nRT

where,

P = Pressure of N_2 gas = 1.00 atm

V = Volume of N_2 gas = ?

n = number of moles N_2 = 0.466 mole

R = Gas constant = 0.0821L.atm/mol.K

T = Temperature of N_2 gas = 22^oC=273+22=295K

Putting values in above equation, we get:

1.00atm\times V=0.466mole\times (0.0821L.atm/mol.K)\times 295K

V=11.3L

As initially no nitrogen was present. So,

Volume expanded = Volume of nitrogen evolved

Thus,

Expansion work = Pressure × Volume

Expansion work = 1.00 atm × 11.3 L

Expansion work = 11.3 L.atm

Conversion used : (1 L.atm = 101.3 J)

Expansion work = 11.3 × 101.3 = 1144.69 J

Therefore, the value of work done for the system is 1144.69 J

5 0
2 years ago
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