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2 years ago

How many moles of pentane are in 1.48x1021

Chemistry

2 answers:

vodka [1.7K]2 years ago

7 0

multiply the number of each atom with its molecular mass. (see the periodic table)

5*12 + 12*1 = 72 gram per mole.

Or more accurately: 5*12.01078 + 12*1.007947 = 72.149264 g/mole

mixer [17]2 years ago

3 0

<h2>Answer:</h2>

1.48 * 1021 number of molecules of pentane = 0.0002458 mol

Given data:

Number of molecules of pentane = 1.48 * 1021

Number of moles = ?

Solution:

1 mole = 6.02 × 1023 molecules.

1 molecule = 1/6.02 × 1023

1.48 × 1021 molecules = (1/6.02 × 1023) × 1.48 × 1021

= 2.458 × 10-3 mol

= 0.0002458 mol

So there are 0.000245 moles of pentane, if the number of molecules are 1.48 * 1021. Because 1 mole mole contain Avogadro's number of molecules.

Which is equal to 6.02 × 1023 molecules.

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Consider the following unbalanced chemical equation. C5H12(l) + O2(g) → CO2(g) + H2O(l) If 21.9 grams of pentane (C5H12) are bur

Marina CMI [18]

Answer : The mass of water produced will be 32.78 grams.

Explanation : Given,

Mass of $C_5H_{12}$ = 21.9 g

Molar mass of $C_5H_{12}$ = 72.15 g/mole

Molar mass of $H_2O$ = 18 g/mole

First we have to calculate the moles of $C_5H_{12}$ .

$\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles$

Now we have to calculate the moles of $H_2O$ .

The balanced chemical reaction will be,

$C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)$

From the balanced reaction we conclude that

As, 1 mole of $C_5H_{12}$ react to give 6 moles of $H_2O$

So, 0.3035 moles of $C_5H_{12}$ react to give $0.3035\times 6=1.821$ moles of $H_2O$

Now we have to calculate the mass of $H_2O$ .

$\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O$

$\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g$

Therefore, the mass of water produced will be 32.78 grams.

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2 years ago

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kolbaska11 [484]

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2 years ago

1. A given mass of air has a volume of 6.00 L at 80.0°C. At constant pressure, the temperature is

earnstyle [38]

3 L will be the final volume for the gas as per Charle's law.

Answer:

Explanation:

The kinetic theory of gases has two significant law which forms the backdrop of motion of gases. They are Charle's law and Boyle's law. As per Charle's law, the volume of any gas molecule at constant pressure is directly proportional to the temperature of the molecule.

V∝ T

Since, here two volumes are given and at two different temperatures with constant pressure. Then as per Charle's law, the relation between the volumes of air at different temperature will be

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2 years ago