<em>The number of atomic orbitals is the same for all elements in a period. Every element in the top row (the first period), for example, has only one orbital for its electrons. The electrons of all the elements in the second row (second period) have two orbitals. Every row adds an orbital as you progress down the table.</em>
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<em>I hope this helps <3</em>
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Answer:
660J/kg.°C
Explanation:
Using the fact that
∆E of metal + ∆E of water = 0
∆E of the metal = Q = m*c*(T2-T1)
Where
Q = heat lost or gained = ?
m = mass of metal in kg = 0.076kg
c = specific heat of the metal = ?
T1 = 96°C
T2=31°C
∆E of the water=Q= m*c*(T2-T1)
Where
Q = 0.120*4180*6.5 = 3260J
Therefore
3,260J + Q of the metal =0
3,260J + 0.076*C*(31.0–96.0)=0
3,260J - 4.94c = 0
3,260 = 4.94c
3,260/4.94 = c
660J/kg.°C = specific heat of the metal
hope this helps:)
Answer:
the research that you do before you start writing your paper or working on your project.
Explanation: