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PilotLPTM [1.2K]
3 years ago
11

what is the pressure, in atmospheres, of 2.97 mol h2 gas if it has a volume of 73 liters when the temperature is 298 k? 0.50 atm

0.060 atm 1.0 atm 2.0 atm
Chemistry
1 answer:
Triss [41]3 years ago
6 0
P x V = n x R x T

P x 73 = 2.97 x 0.082 x 298

P x 73 = 72.57492

P = 72.57492 / 73

P = 1.0 atm

hope this helps!




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What is the new pressure of 150 mL of a gas that is compressed to 50 mL when the original pressure was 3.0 ATM and the temperatu
Arisa [49]

Answer:

\boxed {\boxed {\sf P_2= 9 \ atm}}

Explanation:

Since the temperature is held constant, we only need to focus on the volume and pressure. We will use Boyle's Law, which states the volume of a gas is inversely proportional to the pressure. The formula is:

P_1V_1=P_2V_2

Originally, the gas had a volume of 150 milliliters and a pressure of 3.0 atmospheres. We can substitute these values into the left side of the equation.

3.0 \ atm * 150 \ mL = P_2V_2

The original gas was compressed to a volume of 50 milliliters, but we don't know the volume.

3.0 \ atm *150 \ mL= P_2 * 50 \ mL

Now, we need to solve for the new pressure (P₂). Multiply on the left side first.

450 \ atm*mL= P_2 * 50 \ mL

Since we are solving for the pressure, we need to isolate the variable. It is being multiplied by 50 mL. The inverse of multiplication is division. Divide both sides by 50 mL.

\frac{450 \ atm*mL}{50 \ mL}= \frac{P_2 * 50 \ mL}{50 \ mL}

\frac{450 \ atm*mL}{50 \ mL}= P_2

The units of milliliters will cancel.

\frac{450 \ atm}{50 }= P_2

9 \ atm =P_2

The new pressure is <u>9 atmospheres.</u>

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1.29 g piece of lead has a temperature of 26.0 °C. If it loses 1.90 J of heat to its surroundings, what is its new temperature.
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The new temperature of the piece of lead will be 37.5°C

SPECIFIC HEAT CAPACITY:

  • The amount of heat absorbed or released by a substance can be calculated by using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat absorbed or released (J)

m = mass of substance (g)

c = specific heat capacity

∆T = change in temperature (°C)

According to this question,

Q = 1.90J

m = 1.29g

T1 = 26°C

T2 = ?

c = 0.128 J/g°C

1.90 = 1.29 × 0.128 × (T2- 26°C)

1.90 = 0.165 (T2 - 26°C)

1.90 = 0.165T2 - 4.29

1.90 + 4.29 = 0.165T2

6.19 = 0.165T2

T2 = 37.5°C

Therefore, the new temperature of the piece of lead will be 37.5°C.

Learn more: brainly.com/question/20514651?referrer=searchResults

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Based on the descriptions in the passage, which scientist proposed a model of the atom that matches the
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Answer:

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