Answer:
The temperature must the ring be heated so that the sphere can just slip through is 106.165 °C.
Explanation:
For brass:
Radius = 1.3590 cm
Initial temperature = 23.0 °C
The sphere of radius 1.3611 cm must have to slip through the brass. Thus, on heating the brass must have to attain radius of 1.3611 cm
So,
Δ r = 1.3611 cm - 1.3590 cm = 0.0021 cm
<u>The linear thermal expansion coefficient of a metal is the ratio of the change in the length per 1 degree temperature to its length.</u>
<u>Thermal expansion for brass = 19×10⁻⁶ °C⁻¹</u>
Thus,
Also,
So,
Solving for final temperature as:
<u>Final temperature = 106.165 °C</u>