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4 years ago

Scientists might model the water cycle by using a diagram. What are two

Physics

1 answer:

natta225 [31]4 years ago

5 0

Answer: A and B

Explanation: it says benefits and the other two are not benefits.

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Jenna rides her scooter at a constant speed for 6 km. That part of her ride takes her 1 h. She then

AfilCa [17]

Answer:

5km/h

Explanation:

The equation for average speed is

Vavg = Δd/Δt

where Δd is distance and Δt is time

from what's given, we know she travelled 15km in total and the trip took 3 hours in total. We can now plug in the values into the equation

Vavg = 15/3

Vavg = 5km/h

4 0

3 years ago

A 0.26 kg rod of length 80 cm is suspended by a frictionless pivot at one end. It is held horizontal and released.

Daniel [21]

Answer:

a) $a_{center} = 7.38 ~m/s^2$

b) $a_{end} = 14.77 ~m/s^2$

c) $v_{center} = 2.43~m/s$

Explanation:

a) Immediately after the rod is released, <u>the rod is still horizontal but now subject to gravity.</u> Since one end of the rod is fixed, then the weight of the rod applies a torque. Then by Newton's Second Law, the acceleration can be found.

$\tau =I\alpha$

where I is the moment of inertia of the rod with respect to its fixed end, and α is the angular acceleration.

The net torque of the rod is

$\vec{\tau} = \vec{r} \times \vec{F}\\\tau = rF\sin(90) = rF$

where r is the distance from center of the mass to the fixed end, so r = 0.4 m.

The weight of the rod is w = mg = 0.26 x 9.8 = 2.54 N.

So the net torque is τ = 1.01 Nm.

The moment of inertia of the rod is

$I = \frac{1}{3}mL^2 = \frac{1}{3}(0.26)(0.8)^2 = 0.055~kg m^2$

So, the Newton's Second Law yields

$\tau = I\alpha\\\alpha = \frac{\tau}{I} = \frac{1.01}{0.055} = 18.47$

<u>The relation between angular acceleration and linear acceleration is a = αr </u>

So, the linear acceleration of the rod is

$a = \alpha r = 7.38~m/s^2$

b) Using the same relationship between angular acceleration and linear acceleration, the linear acceleration of the end of the rod can be found.

$a = \alpha L = 14.77~m/s^2$

c) The conservation of energy can be used to find the velocity when the rod is vertical.

$K_1 + U_1 = K_2 + U_2\\0 + mg(L/2) = \frac{1}{2}I\omega^2 + 0\\(0.26)(9.8)(0.4) = \frac{1}{2}(0.055)\omega^2\\\omega = 6.08~rad/s$

The linear velocity is v = ωr, so

v = 2.43 m/s.

4 0

3 years ago

What color does the star alpha centauri appear to be?

myrzilka [38]

B.yellow-white is the answer.

3 0

3 years ago

Read 2 more answers

Across what potential difference does an electron have to be accelerated in order to reach the speed v=3e7 m/s?

zmey [24]

When an electron is accelerated through potential difference then the speed that it attain will be explained by energy conservation

here by energy conservation we can say that

change in kinetic energy of electron = electrostatic potential energy gained through given potential difference

kinetic energy is given as

$KE = \frac{1}{2}mv^2$

electrostatic potential energy is given as

$PE = qV$

now by energy conservation

$qV = \frac{1}{2}mv^2$

given that for electron

$m = 9.1 * 10^{-31} kg$

$v = 3 * 10^7 m/s$

$q = 1.6 * 10^{-19} C$

now by plug in values

$1.6 * 10^{-19} * V = \frac{1}{2}*9.1* 10^{-31} *(3*10^7)^2$

$V = \frac{4.095 * 10^{-16}}{1.6 * 10^{-19}}$

$V = 2559.4 Volts$

So here it is accelerated through potential difference of 2559.4 Volts

4 0

3 years ago

2. Which answer is the closest to the net force of a 4 N force right and a 7 N force upward?

AfilCa [17]

Answer:

11 N up-right

Explanation:

it is

6 0

3 years ago