I would say B but I have no clue
Kinetic energy = (1/2) (mass) x (speed)²
At 7.5 m/s, the object's KE is (1/2) (7.5) (7.5)² = 210.9375 joules
At 11.5 m/s, the object's KE is (1/2) (7.5) (11.5)² = 495.9375 joules
The additional energy needed to speed the object up from 7.5 m/s
to 11.5 m/s is (495.9375 - 210.9375) = <em>285 joules</em>.
That energy has to come from somewhere. Without friction, that's exactly
the amount of work that must be done to the object in order to raise its
speed by that much.
Answer:
r₂ = 0.316 m
Explanation:
The sound level is expressed in decibels, therefore let's find the intensity for the new location
β = 10 log
let's write this expression for our case
β₁ = 10 log \frac{I_1}{I_o}
β₂ = 10 log \frac{I_2}{I_o}
β₂ -β₁ = 10 (
)
β₂ - β₁ = 10
log \frac{I_2}{I_1} =
= 3
= 10³
I₂ = 10³ I₁
having the relationship between the intensities, we can use the definition of intensity which is the power per unit area
I = P / A
P = I A
the area is of a sphere
A = 4π r²
the power of the sound does not change, so we can write it for the two points
P = I₁ A₁ = I₂ A₂
I₁ r₁² = I₂ r₂²
we substitute the ratio of intensities
I₁ r₁² = (10³ I₁ ) r₂²
r₁² = 10³ r₂²
r₂ = r₁ / √10³
we calculate
r₂ =
r₂ = 0.316 m
Despite the risks, Human populations can be found near volcanoes. This can be associated with the availability of which natural resource?
- <em>Geothermal</em><em> </em><em>energy</em>
<u>Geothermal</u><u> </u><u>energy</u><u> </u><u>is</u><u> </u><u>the</u><u> </u><u>f</u><u>o</u><u>r</u><u>m</u><u> </u><u>of</u><u> </u><u>energy</u><u> </u><u>obtained</u><u> </u><u>from</u><u> </u><u>the</u><u> </u><u>heat</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>earth</u><u>.</u><u> </u><u>Near</u><u> </u><u>volcanoes</u><u> </u><u>the</u><u> </u><u>land</u><u> </u><u>is</u><u> </u><u>more</u><u> </u><u>hot</u><u> </u><u>compared</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>normal</u><u> </u><u>areas</u><u>.</u><u> </u><u>So</u><u>,</u><u> </u><u>the</u><u> </u><u>heat</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>lava</u><u> </u><u>will</u><u> </u><u>help</u><u> </u><u>in</u><u> </u><u>producing</u><u> </u><u>Geothermal</u><u> </u><u>energy</u><u>.</u><u>.</u><u>.</u><u>~</u>
Answer:
Average speed = distance/time
From 1 to 9 seconds:
Distance covered = 1 - 0.2 = 0.8 km
Time = 9 - 1 = 8 sec
Average speed = 0.8 km / 8 sec
Average speed = 0.1 km/s .
The average speed for the whole test is 1.6 km / 20 sec = 0.08 km/sec. A graph of speed vs time would average out as a horizontal line at 0.08 km/sec from 1 sec to 21 sec. The area under it would be (0.08 km/s) x (20 sec) = 1.6 km.
Surprise surprise ! The area under a speed/time graph is the distance covered during that time !
In closing, I want to express my gratitude for the gracious bounty of 3 points with which I have been showered. Moreover, the green breadcrust and tepid cloudy water have also been refreshing.
Explanation: