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2 years ago

What is the Galaxy we live in called?

Physics

2 answers:

Fittoniya [83]2 years ago

7 0

The Milky Way is a spiral galaxy type so it has arms sort of like an octopus. We live in the Milky Way

Yuki888 [10]2 years ago

6 0

Milky Way is spiral galaxy type so it arm sort of an octopus that's what we like in . I hope this helps(:

You might be interested in

Distinguish between resultant and equilibrant forces<br><br><br>

SIZIF [17.4K]

Answer:

resultant is a single force that can replace the of a number of forces , equililbrant is a force that is exactly opposite to resultant

Explanation:

4 0

3 years ago

Shah did not trust the results of an experiment that she had read about, so she is conducting the experiment herself. She goes t

Hitman42 [59]

The question is incomplete, the complete question is;

Shah did not trust the results of an experiment that she had read about, so she is conducting the experiment herself. She goes through the same set of steps and measures the effect of the amount of sugar on a single organism.

Which best describes what Shah is doing?

replication

repetition

both repetition and replication

neither repetition nor replication

Answer:

replication

Explanation:

Replication in scientific experiments refer to the process of going through all the steps in an experiment in order to obtain the same set of results initially obtained.

All scientific experiments is expected to be replicated under identical experimental conditions. If the results obtained by a scientific investigation cannot be replicated under identical circumstances by other scientists, then the scientific data must be taken with a pinch of salt.

Shah is expected to obtain almost exactly the same data as the original researchers who first published the data.

5 0

2 years ago

Read 2 more answers

Kalea throws a baseball directly upward at time t = 0 at an initial speed of 13.7 m/s. How high h does the ball rise above its r

Trava [24]

Answer:

h = 9.57 seconds

Explanation:

It is given that,

Initial speed of Kalea, u = 13.7 m/s

At maximum height, v = 0

Let t is the time taken by the ball to reach its maximum point. It cane be calculated as :

$v=u-gt$

$u=gt$

$t=\dfrac{u}{g}$

$t=\dfrac{13.7}{9.8}$

t = 1.39 s

Let h is the height reached by the ball above its release point. It can be calculated using second equation of motion as :

$h=ut+\dfrac{1}{2}at^2$

Here, a = -g

$h=ut-\dfrac{1}{2}gt^2$

$h=13.7\times 1.39-\dfrac{1}{2}\times 9.8\times (1.39)^2$

h = 9.57 meters

So, the height attained by the ball above its release point is 9.57 meters. Hence, this is the required solution.

7 0

3 years ago

A square sheet of rubber has sides that are 20 cm long. What is the area of the square of rubber in cm squared?

Alinara [238K]

Answer:

400cm^2

Explanation:

sides are 20cm long Area for a square is a squared

since all the lides are of equal length you can just choose one side.

20squared is 400

20 x 20 = 400cm squared

Hope this helps :)

6 0

3 years ago

How do I do this physics problem about potential energy and kinetic energy?

larisa86 [58]

Ok i apologise for the messy working but I'll try and explain my attempt at logic

Also note i ignore any air resistance for this.

First i wrote the two equations I'd most likely need for this situation, the kinetic energy equation and the potential energy equation.

Because the energy right at the top of the swing motion is equal to the energy right in the "bottom" of the swing's motion (due to conservation of energy), i made the kinetic energy equal to the potential energy as indicated by Ek = Ep.

I also noted the "initial" and "final" height of the swing with hi and hf respectively.

So initially looking at this i thought, what the heck, there's no mass. Then i figured that using the conservation of energy law i could take the mass value from the Ek equation and use it in the Ep equation. So what i did was take the Ek equation and rearranged it for m as you can hopefully see. Then i substituted the rearranged Ek equation into the Ep equation.

So then the equation reads something like Ep = (rearranged Ek equation for m) × g (which is -9.81) × change in height (hf - hi).

Then i simplify the equation a little. When i multiply both sides by v^2 i can clearly see that there is one E on each side (at that stage i don't need to clarify which type of energy it is because Ek = Ep so they're just the same anyway). So i just canceled them out and square rooted both sides.

The answer i got was that the max velocity would be 4.85m/s 3sf, assuming no losses (eg energy lost to friction).

I do hope I'm right and i suppose it's better than a blank piece of paper good luck my dude xx

4 0

2 years ago