Answer:
Thus, the time for the first lamp is 44 minutes.
Explanation:
Power of first lamp, P' = 1000 W
Power of second lamp, P'' = 4400 W
time for second lamp, t'' = 10 minutes
Let the time for first lamp is t'.
As the energy is same, so,
P' x t' = P'' x t''
1000 x t' = 4400 x 10
t' = 44 minutes
Here the block has two work done on it
1. Work done by gravity
2. Work done by friction force
So here it start from height "h" and then again raise to height hA after compressing the spring
So work done by the gravity is given as
![W_g = m_A g(h - h_A)](https://tex.z-dn.net/?f=W_g%20%3D%20m_A%20g%28h%20-%20h_A%29)
Now work done by the friction force is to be calculated by finding total path length because friction force is a non conservative force and its work depends on total path
![W_f = -(\mu m_A g cos\theta)(\frac{h}{sin\theta} + \frac{h_A}{sin\theta})](https://tex.z-dn.net/?f=W_f%20%3D%20-%28%5Cmu%20m_A%20g%20cos%5Ctheta%29%28%5Cfrac%7Bh%7D%7Bsin%5Ctheta%7D%20%2B%20%5Cfrac%7Bh_A%7D%7Bsin%5Ctheta%7D%29)
![W_f = -\mu m_A g cot\theta(h + h_A)](https://tex.z-dn.net/?f=W_f%20%3D%20-%5Cmu%20m_A%20g%20cot%5Ctheta%28h%20%2B%20h_A%29)
Total work done on it
![W = m_A g(h - h_A) - \mu m_A g cot\theta(h + h_A)](https://tex.z-dn.net/?f=W%20%3D%20m_A%20g%28h%20-%20h_A%29%20-%20%5Cmu%20m_A%20g%20cot%5Ctheta%28h%20%2B%20h_A%29)
So answer will be
None of these
Refraction is the bending of a wave disturbance as it passes at an angle from one medium into another
Answer:
Acceleration
![\frac{distace}{time}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bdistace%7D%7Btime%7D%20)
When we cross multiply, distance will be equal to acceleration multiply by time
Distance = acceleration x time
Distance = 9.8 x 3
= 29.4 m/s