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zzz [600]
3 years ago
6

What Is the acceleration of a toy car that starts from rest and has a speed of 0.12 m/s after 0.1?

Physics
1 answer:
VikaD [51]3 years ago
6 0

Given: Initial velocity of toy car (u ) = 0

Final velocity of toy car (v) = 0.12 m/s

Required time (t) = 0.1 s

To find: The acceleration of the toy car.

Let the acceleration of the toy car be (a)

Formula Used: 1st kinematic equation of motion

                              v = u + at ---------------------------(i)

Here, all alphabets are in their usual meanings

Now, from equation (i), we shall calculate the value of 'a'.

so,                          a = (v - u) /t

or,                          a = (0.12 m/s - 0) / 0.1s

or,                          a = 1.2 m/s²

Hence, the required acceleration of the toy car will be 1.2 m/s².

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It would be impossible to build a microscope that could use visible light to see the molecular structure of a crystal because. I
Serhud [2]

Answer:

the correct one is: a diffraction limits the resolving power to approximately the size of the wavelength of the light used

Explanation:

To be able to solve two structures with a light source, the Rayleigh criterion must be met that stable the two structures are solved when the first minimum of diffraction at one point is in the code of the first maximum of the other point

Using this criterion we can find an expression for the first minimization of the diffraction spectrum m = 1

     sin θ tea = λ / a

now the structure of the comatose has a separation of around 1 nm and the wavelength of visible light ranges from 400 to 700 nm, when substituting we find

           sin θ = 400/1 10

           sin θ  = 400

           sin θ  = 700/1

           sin θ  = 700

These values ​​are neither impossible since the sin function is bounded between -1 to 1, so we cannot see the diffraction

When reviewing the different statements, the correct one is: a diffraction limits the resolving power to approximately the size of the wavelength of the light used:

6 0
2 years ago
One horsepower (1 hp) is the unit of power based on the work that a horse can do in one second. This is defined, in English unit
nikdorinn [45]

Power is defined as rate of work done which means it is work done in 1 second of time

Now it is given that we have a horse that will give power 745.7 W

So it will do work of 745.7 J in  1 second of time

now if we wish to find the work done by horse in 0.55 s

so we can say

W = Power \times time

W = 745.7 \times 0.55

W = 410.14 J

So it will do total work of 410.14 J in 0.55 s of time

7 0
3 years ago
which properties change the composition of a substance? A) physical properties B) neither chemical nor physical properties C) ch
svlad2 [7]

Answer:

C) chemical properties is the answer....

8 0
2 years ago
How much potential energy foes a 5kg mass have when its 2 meters above the ground?(Hint :PE=m*g*h)​
frez [133]

Answer:

<h2>98 J</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

PE = 5 × 9.8 × 2

We have the final answer as

<h3>98 J</h3>

Hope this helps you

5 0
2 years ago
A ball is thrown with a speed of 20 m/s at an angle of 40o above the horizontal from the top of a 22-m tall building.
MrRissso [65]

Answer:

(a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

Explanation:

Given that,

Speed = 20 m/s

Angle = 40°

Height = 22 m

Time = 3.25 sec

(a). We need to calculate the distance

Using formula of distance

d=u\cos\theta\times t

Put the value into the formula

d=20\cos40\times3.25

d=49.79\ m

(b). We need to calculate the horizontal velocity

Using formula of velocity

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=20\times\cos40

v_{x}=15.3\ m/s

We need to calculate the vertical velocity

Using equation of motion

v_{y}=u\sin\theta-gt

Put the value into the formula

v_{y}=20\sin40-9.8\times3.25

v_{y}=-19\ m/s

Negative sign shows the opposite direction.

We need to calculate the speed of ball

Using formula of speed

v=\sqrt{v_{x}^2+v_{y}^2}

v=\sqrt{(15.3)^2+(19)^2}

v=24.39\ m/s

Hence, (a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

4 0
2 years ago
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