Question

What are the critical points for the inequality x^2-9x/x-5 < 0?

Answer 1

Answer:

the critical points are 0,5,9

Step-by-step explanation:

Answer 2

Answer:

0, 5 and 9

Step-by-step explanation:

The critical points for any inequality are the points for which the numerator of the denominator equal 0.

Here, we are given the following inequality:

$\frac { x^2 - 9x } { x - 5 } < 0$

So the critical points will be where$x^2 - 9x = 0$ and where $x - 5 = 0$.

$x^2 - 9x = 0$

$x (x - 9) = 0$

$x = 0 and x = 9$

$x - 5 = 0$

$x = 5$

Therefore, the critical points for the given inequality are 0, 5 and 9.