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PtichkaEL [24]
3 years ago
7

Two planets having equal masses are in circular orbit around a star. Planet A has a smaller orbital radius than planet B. Which

statement is true?Planet A has more kinetic energy, less potential energy, and less mechanical energy (potential plus kinetic) than planet B.Planet A has more kinetic energy, less potential energy, and more mechanical energy (potential plus kinetic) than planet B.Planet A has more kinetic energy, more potential energy, and more mechanical energy (potential plus kinetic) than planet B.Planet A and planet B have the same amount of mechanical energy (potential plus kinetic).
Physics
1 answer:
vova2212 [387]3 years ago
6 0

Answer:

Explanation:

To solve this, we must know two things.

First, the force of gravity acting on an orbiting object is equal to its mass times centripetal acceleration.

Second, the force of gravity between two objects is defined by Newton's law of universal gravitation: Fg = mMG/r², where Fg is the force of gravity, m and M are the masses of the objects, G is the universal constant of gravitation, and r is the distance between the objects.

Therefore:

Fg = m v²/r

mMG/r² = m v²/r

v² = MG/r

The potential energy of each planet is:

PE = mgr = m (MG/r²) r = mMG/r

The kinetic energy of each planet is:

KE = 1/2 mv² = 1/2 m (MG/r) = 1/2 mMG/r

The total mechanical energy is:

ME = PE + KE = 3/2 mMG/r

Since both planets have the same mass, the only difference is the orbital radius.  Since planet A has a smaller orbital radius, it has more potential energy, more kinetic energy, and more mechanical energy.

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PLEASE HELP!!! GIVING BRAINLIEST!! ill also answer questions that you have posted if you answer this correctly!!!! (40pts)
melisa1 [442]
D.)downward toward the center of earth
7 0
3 years ago
Which of the following types of energy originates below Earth's surface?
faltersainse [42]
Geothermal energy. Electromagnetic energy originates at the sun (think UV rays; they are part of the electromagnetic spectrum). Electrical energy technically can be anywhere, as long as there are positive and negative charges. Mechanical energy is like a generator or an engine; there is always something working to get things done/made. I hope this answer and these explanations helped!
6 0
3 years ago
A ball with a mass of 275 g is dropped from rest, hits the floor, and re-bounds upward. If the ball hits the floor with a speed
disa [49]

Answer:

a) \Delta p = 1.350\,\frac{kg\cdot m}{s}, b) \Delta p' = -0.454\,\frac{kg\cdot m}{s}, c) D. The magnitud of the change in the ball's momentum.

Explanation:

a) The magnitude of the change in the ball's momentum is:

\Delta p = (0.275\,kg)\cdot \left[\left(1.63\,\frac{m}{s} \right)-\left(-3.28\,\frac{m}{s} \right)\right]

\Delta p = 1.350\,\frac{kg\cdot m}{s}

b) The change in the magnitude of the ball's momentum:

\Delta p' = (0.275\,kg)\cdot \left[(1.63\,\frac{m}{s} )-(3.28\,\frac{m}{s} ) \right]

\Delta p' = -0.454\,\frac{kg\cdot m}{s}

c) The magnitude of the change in the ball's momentum is more directly related to the net force acting on the ball, as it measures the effect of the force on change in ball's motion at measured time according to the Impact Theorem. So, the right answer is option D.

3 0
3 years ago
Solve the following two equations for the (positive) time, t, and the position, x. Assume SI units.
Luden [163]

A system of equations is a group of equations with the same variables that we need to solve simultaneously. Such that the solutions is given by the intersection betweens graphs of the functions.

We will see that the solution is (16.4, 807.0)

Here the system is:

x = 3.00*t^2\\x = 45.0*t + 69.0

To solve a system we usually need to isolate one of the variables in one equation and replace that in the other equation, here we already see that we have x isolated in the two equations, so we can write:

3.00*t^2 = x = 45.0*t + 69.0\\3.00*t^2 = 45.0*t + 69.0

Now we can solve the above equation for t:

3.00*t^2 = 45.0*t + 69.0\\\\3.00*t^2 - 45.0*t - 69.0 = 0

This is just a quadratic equation, the solution is given by the Bhaskara's formula, we will get:

t = \frac{-(-45.0) \pm \sqrt{(-45.0)^2 - 4*(3.00)*(-69.0)} }{2*3.00} \\\\t = \frac{{(45.0) \pm 53.4} }{6.00}

Then the two values of t are:

t = (45.0 + 53.4)/6 = 16.4

t = (45.0 - 53.4)/6 = -1.4

We want the positive solution, so we choose t = 16.4

To complete the solution we need to evaluate one of our functions in this time. Let's use the first one:

x = 45.0*16.4 + 69.0 = 807.0

Then the solution is:

(16.4, 807.0)

If you want to learn more you can read:

brainly.com/question/12895249

5 0
3 years ago
1. A 20m steel wire is stretched to 20.0m by
Eduardwww [97]

Answer:

Force to stretch the wire is 250 N

Explanation:

As we know that modulus of elasticity will remain the same for the wire if the applied stretch to the wire is within elastic limit

So we will have

\frac{F L}{\Delta L A} = constant

now we have

\frac{F_1 L}{\Delta L_1 A} = \frac{F_2 L}{\Delta L_2 A}

so we can write it as

F_2 = \frac{F_1 L_2}{L_1}

F_2 = \frac{50 (0.05)}{0.01}

F_2 = 250 N

7 0
3 years ago
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