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PtichkaEL [24]
3 years ago
7

Two planets having equal masses are in circular orbit around a star. Planet A has a smaller orbital radius than planet B. Which

statement is true?Planet A has more kinetic energy, less potential energy, and less mechanical energy (potential plus kinetic) than planet B.Planet A has more kinetic energy, less potential energy, and more mechanical energy (potential plus kinetic) than planet B.Planet A has more kinetic energy, more potential energy, and more mechanical energy (potential plus kinetic) than planet B.Planet A and planet B have the same amount of mechanical energy (potential plus kinetic).
Physics
1 answer:
vova2212 [387]3 years ago
6 0

Answer:

Explanation:

To solve this, we must know two things.

First, the force of gravity acting on an orbiting object is equal to its mass times centripetal acceleration.

Second, the force of gravity between two objects is defined by Newton's law of universal gravitation: Fg = mMG/r², where Fg is the force of gravity, m and M are the masses of the objects, G is the universal constant of gravitation, and r is the distance between the objects.

Therefore:

Fg = m v²/r

mMG/r² = m v²/r

v² = MG/r

The potential energy of each planet is:

PE = mgr = m (MG/r²) r = mMG/r

The kinetic energy of each planet is:

KE = 1/2 mv² = 1/2 m (MG/r) = 1/2 mMG/r

The total mechanical energy is:

ME = PE + KE = 3/2 mMG/r

Since both planets have the same mass, the only difference is the orbital radius.  Since planet A has a smaller orbital radius, it has more potential energy, more kinetic energy, and more mechanical energy.

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An empty parallel plate capacitor is connected between the terminals of a 18.8-V battery and charges up. The capacitor is then d
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Answer:

p.d' = 37.6 V

Explanation:

From the question we are told that:

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C=\frac{eA}{d}

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7 0
3 years ago
Three small balls of the same size but different masses are hung side-by-side in parallel on the strings of same length. They to
andrey2020 [161]

Answer:

m1/6 ( c )

Explanation:

since all the balls starts having the same momentum after the two collisions we will apply the principal of conservation of energy

After first collision

m1v = m1v1 + m2v2 --- ( 1 )

After second collision

m2v2 = m2v2 + m3v3   ---- ( 2 )

combining equations 1 and 2

m1v = m1v1 + m2v2 + m3v3  ----- ( 3 )

All balls moving at the same momentum ( p ) = m1v1 = m2v2 = m3v3

note ; 3p = m1v ∴ m3 = \frac{m1v}{3v3}  -----  ( 4 )

applying conservation of energy

3v = v1 + v2 + v3 ------- ( 5 )

also 3m1v1 = m1v = v1 = v/3 =

v2 + v3 = 8/3 v ----- ( 6 )

next eliminate V3 for equation 6 by applying conservation of energy and momentum

m1 =  2m2 ------ ( 7 )

now using p1 = p2 = m1v1 = 1/2 m1v1  hence v2 = 2v1  where v1 = 1/3 v

hence ; v2 = 2/3 v ------- ( 8 )

solving with equation 6 and 8

v3 = 2v ------ ( 9 ) ∴  v/v3 = 1/2 ---- ( 10 )

solving with equation 9 and 10

m3 = m1/3 * 1/2 = m1/6

8 0
3 years ago
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