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PtichkaEL [24]
3 years ago
7

Two planets having equal masses are in circular orbit around a star. Planet A has a smaller orbital radius than planet B. Which

statement is true?Planet A has more kinetic energy, less potential energy, and less mechanical energy (potential plus kinetic) than planet B.Planet A has more kinetic energy, less potential energy, and more mechanical energy (potential plus kinetic) than planet B.Planet A has more kinetic energy, more potential energy, and more mechanical energy (potential plus kinetic) than planet B.Planet A and planet B have the same amount of mechanical energy (potential plus kinetic).
Physics
1 answer:
vova2212 [387]3 years ago
6 0

Answer:

Explanation:

To solve this, we must know two things.

First, the force of gravity acting on an orbiting object is equal to its mass times centripetal acceleration.

Second, the force of gravity between two objects is defined by Newton's law of universal gravitation: Fg = mMG/r², where Fg is the force of gravity, m and M are the masses of the objects, G is the universal constant of gravitation, and r is the distance between the objects.

Therefore:

Fg = m v²/r

mMG/r² = m v²/r

v² = MG/r

The potential energy of each planet is:

PE = mgr = m (MG/r²) r = mMG/r

The kinetic energy of each planet is:

KE = 1/2 mv² = 1/2 m (MG/r) = 1/2 mMG/r

The total mechanical energy is:

ME = PE + KE = 3/2 mMG/r

Since both planets have the same mass, the only difference is the orbital radius.  Since planet A has a smaller orbital radius, it has more potential energy, more kinetic energy, and more mechanical energy.

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The aorta is approximately 25 mm in diameter. The mean pressure there is about 100 mmHg and the blood flows through the aorta at
Ksenya-84 [330]

Answer:

Explanation:

25 mm diameter

r₁  = 12.5 x 10⁻³ m radius.

cross sectional area =  a₁

Pressure P₁  = 100 x 10⁻³ x 13.6 x 9.8 Pa

a )

velocity of blood v₁ = .6 m /s

Cross sectional area at blockade = 3/4 a₁

Velocity at blockade area = v₂

As liquid is in-compressible

a₁v₁ = a₂v₂

a₁ x .6 m /s  = 3/4 a₁ v₂

v₂ = .8m/s

b )

Applying Bernauli's theorem formula

P₁ + 1/2 ρv₁² =  P₂ +  1/2 ρv₂²

100 x 10⁻³ x 13.6 x10³x 9.8 + 1/2 X 1060 x .6² = P₂ +  1/2x 1060 x .8²

13328 +190.8 = P₂ + 339.2

P₂ = 13179.6 Pa

= 13179 / 13.6 x 10³ x 9.8 m of Hg

P₂ =  .09888 m of Hg

98.88 mm of Hg

8 0
4 years ago
What is the net force required to accelerate a 884 kg car at 2 m/sec2?
EastWind [94]

Answer:

1768 N

Explanation:

We can solve the problem by using Newton's second law:

F=ma

where

F is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, we have a car of mass

m = 884 kg

And its acceleration is

a=2 m/s^2

Substituting into the equation, we find the net force on the car:

F=(884)(2)=1768 N

3 0
3 years ago
Which type of mirror always has an image that is smaller than the object?
BaLLatris [955]

Which type of mirror always has an image that is smaller than the object?

convex

7 0
3 years ago
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Do magnets have to touch each other in order to experience a magnetic<br> force? Explain
tiny-mole [99]
Magnets don’t need to touch each other in order to be magnetic because all objects have an attraction however, the closer the magnets get, the more magnetic it is.
4 0
3 years ago
If the core of jupiter is 30,000 celcius and it is five times hotter than the sun, what's the temperature of the surface of the
VMariaS [17]
Let, the temperature of Sun's surface = c

So, 5c = 30, 000
c = 30,000 / 5
c = 6,000

In short, Your Answer would be 6000

Hope this helps!
6 0
4 years ago
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