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3 years ago

Glyceraldehyde-3-phosphate is an important intermediate molecule in the cell's metabolic pathways because __________.

Chemistry

1 answer:

olga55 [171]3 years ago

4 0

Answer:

Present in both catabolic and anabolic pathways

Explanation:

Glyceraldehyde-3-phosphate abbreviated as G3P occurs as intermediate in glycolysis and gluconeogenesis.

In photosynthesis, it is produced by the light independent reaction and acts as carrier for returning ADP, phosphate ions Pi, and NADP+ to the light independent pathway. Photosynthesis is a anbolic pathway.

In glycolysis, Glyceraldehyde-3-phosphate is produced by breakdown of fructose-1,6 -bisphosphate. Further Glyceraldehyde-3-phosphate converted to pyruvate and pyruvate is further used in citric acid cycle for energy production. Therefore, it is used in catabolic pathway too.

Glyceraldehyde-3-phosphate is an important intermediate molecule in the cell's metabolic pathways because it is present in both catabolic and anabolic pathways.

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Write the Lewis structure for the product that forms when boron trifluoride combines with ammonia. Remember to show all non-zero

horrorfan [7]

Answer:

To draw or sketch a Lewis structure, formula or diagram, the chemical formula of the compound is essential. Without it you can not even know what are the atoms that make it up, in our case it is the one observed in the reaction shown:

$BF_{3}$ + $:NH_{3}$ ⇒ F3 $F_{3} BNH_{3}$

In the structure obtained (see the Lewis structure in the drawing) the black dots correspond to the electrons of the non-shared pairs. Because hydrogen has a single electron and a single orbital available to fill, it forms only a covalent bond represented by a long dash. The same goes for boron and fluorine but in this case the fluorine has pairs of free electrons.

Explanation:

Lewis's structure is all that representation of covalent bonds within a molecule or an ion. In it, said bonds and electrons are represented by long dots or dashes, although most of the times the dots correspond to non-shared electrons and dashes to covalent bonds.

All existing compounds can be represented by Lewis structures, giving a first approximation of how the molecule or ions could be.

8 0

3 years ago

Identify the reaction that occurs when the acid hbr is added to the buffer solution. Add hbr

Tamiku [17]

Hmmm hard to tell. Sorrry :(/((/(/

7 0

3 years ago

Which of the following elements should have properties similar to those of nitrogen

exis [7]

Answer:

Nitrogen group element, any of the chemical elements that constitute Group 15 (Va) of the periodic table. The group consists of nitrogen (N), phosphorus (P), arsenic (As), antimony (Sb), bismuth (Bi), and moscovium (Mc)

Explanation: Hope i helped! :D

8 0

3 years ago

Determine the oxidation states of the elements in the compounds listed. None of the oxygen-containing compounds are peroxides or

choli [55]

Explanation:

a) $H_2SO_4$

oxidation state of H = +1

Oxidation state of O = -2

Let the oxidation no. of S be x.

$2\times1+ x+2\times -4 =0$

$2 +x-8 = 0\\x=+6$

Oxidation state of S in $H_2SO_4$ = +6

b) $Ca(OH)_2$

oxidation state of H = +1

Oxidation state of O = -2

Let the oxidation no. of Ca be x.

$x+2\times-2+2\times+1 =0\\x=4 -2\\x=+2$

Oxidation state of Ca in $Ca(OH)_2$ = +2

c) BrOH

oxidation state of H = +1

Oxidation state of O = -2

Let the oxidation no. of Br be x.

$x+1\times-2+1\times+1 =+1$

Oxidation no. of Br in BrOH is +1

d) $ClNO_2$

oxidation state of Cl = -1

Oxidation state of O = -2

Let the oxidation no. of N be x.

$-1+x+2\times-2\\x = 4+1 =+5$

Oxidation state of N in $ClNO_2$ = +3

e) $TiCl_4$

oxidation state of Cl = -1

Let the oxidation no. of Ti be x.

$x+4\times -1 = 0\\x=+4$

Oxidation state of Ti in $TiCl_4$ = +4

f) NaH

Na is more electropositive than H.

Therefore, oxidation state of Na = +1

Oxidation state of H = -1

6 0

3 years ago

What is the salinity of nitrogen?

yuradex [85]

Answer:

the concentration of nitrogen in shoots and roots was greatest at 14 mg N T^ At each nitrogen level, increase in salinity significantly decreased nitrogen concentrations in shoots and roots.

HOPE I HELPED

∫∫-Depree

8 0

3 years ago