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3 years ago

Glyceraldehyde-3-phosphate is an important intermediate molecule in the cell's metabolic pathways because __________.

Chemistry

1 answer:

olga55 [171]3 years ago

4 0

Answer:

Present in both catabolic and anabolic pathways

Explanation:

Glyceraldehyde-3-phosphate abbreviated as G3P occurs as intermediate in glycolysis and gluconeogenesis.

In photosynthesis, it is produced by the light independent reaction and acts as carrier for returning ADP, phosphate ions Pi, and NADP+ to the light independent pathway. Photosynthesis is a anbolic pathway.

In glycolysis, Glyceraldehyde-3-phosphate is produced by breakdown of fructose-1,6 -bisphosphate. Further Glyceraldehyde-3-phosphate converted to pyruvate and pyruvate is further used in citric acid cycle for energy production. Therefore, it is used in catabolic pathway too.

Glyceraldehyde-3-phosphate is an important intermediate molecule in the cell's metabolic pathways because it is present in both catabolic and anabolic pathways.

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Why metal in the middle of metal activity series can't be obtained by heating ors in air

maxonik [38]

Answer:

See Explanation

Explanation:

The way by which a metal is obtained from its ore is determined by the chemical reactivity of the metal.

Metals that are highly reactive are chiefly obtained by electrolysis of the metal salt. These metals are found high up in the metal activity series.

Metals that are at the middle of the series are moderately reactive and are obtained by electrolysis or by reduction since they still form ionic salts.

Metals that are far lower in the series can only be obtained by heating them in air because they are mostly unreactive.

Hence, moderately reactive metals at the middle of the series are not obtained by roasting in air.

3 0

3 years ago

Wont more BRAINLYS just answer the question right

aniked [119]

Answer:

1. A.

2. D.

3. E.

4. B

5. C.

Explanation:

1. The water cycle uses radiant energy from the sun to function

2. Crystals form by crystalization, hence the name.

3. Condensation is when water vapor changes to a liquid.

4. The water cycle is the movement of water on earth on and below it's crust.

5. Transperation is how plants release water into the air. Also how humans sweat.

Have a most wonderous day!

4 0

3 years ago

How many moles of AgNO3 must react to form 0. 854 mol Ag? mol AgNO3.

babunello [35]

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

The balanced chemical equation for the dissolution of silver nitrate has been:

$\rm AgNO_3\;\rightarrow\;Ag^+\;+\;NO_3^-$

The aqueous solution of silver nitrate has been dissociated into the constituent silver and nitrate ions.

In a balanced chemical equation, the coefficient has been equivalent to the moles of each reactant forming the moles of product.

From, the balanced equation,

$\rm 1\;mol\;AgNO_3=1\;mol\;Ag$

The given moles of Silver has been 0.854 mol. Thus, the moles of silver nitrate required has been given as:

$\rm 1\;mol\;Ag^+=1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;\times\;1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;mol\;AgNO_3$

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

For more information about the moles produced, refer to the link:

brainly.com/question/10606802

6 0

2 years ago

H2(g) + F2(g)2HF(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.20 moles

abruzzese [7]

<u>Answer:</u> The value of $\Delta S^o$ for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

$\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]$

For the given chemical reaction:

$H_2(g)+F_2(g)\rightarrow 2HF(g)$

The equation for the entropy change of the above reaction is:

$\Delta S^o_{rxn}=[(2\times \Delta S^o_{(HF(g))})]-[(1\times \Delta S^o_{(H_2(g))})+(1\times \Delta S^o_{(F_2(g))})]$

We are given:

$\Delta S^o_{(HF(g))}=173.78J/K.mol\\\Delta S^o_{(H_2)}=130.68J/K.mol\\\Delta S^o_{(F_2)}=202.78J/K.mol$

Putting values in above equation, we get:

$\Delta S^o_{rxn}=[(2\times (173.78))]-[(1\times (130.68))+(1\times (202.78))]\\\\\Delta S^o_{rxn}=14.1J/K$

Entropy change of the surrounding = - (Entropy change of the system) = -(14.1) J/K = -14.1 J/K

We are given:

Moles of hydrogen gas reacted = 2.20 moles

By Stoichiometry of the reaction:

When 1 mole of hydrogen gas is reacted, the entropy change of the surrounding will be -14.1 J/K

So, when 2.20 moles of hydrogen gas is reacted, the entropy change of the surrounding will be = $\frac{-14.1}{1}\times 2.20=-31.02J/K$

Hence, the value of $\Delta S^o$ for the surrounding when given amount of hydrogen gas is reacted is -31.02 J/K

7 0

3 years ago

How is the number of valence electrons related to the ionization energy of an element?

Elina [12.6K]

A) Low ionization energy correlates to elements with fewer valence electrons.

Ionization energy is the energy required to separate valence electrons from their atom. The more valence electrons there are, the higher the ionization energy.

Hope this helps!

8 0

3 years ago