The concentration of diluted solution is 0.756M.
From the question given above, the following data were obtained:
Volume of stock solution (V1) = 18.9 mL
Molarity of stock solution (M1) = 10 M
Volume of diluted solution (V2) = 250 mL
Molarity of diluted solution (M2) =?
We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:
M1V1 = M2V2
10 × 18.9 = M2 ×250
189 = M2 × 250
Divide both side by 100
M2 = 189 / 250
M2 = 0.756 M
Therefore, the molarity of the diluted solution is 0.756 M.
Thus the concluded that concentration of the dilute acid is 0.756 M.
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Answer:
Number of moles of chlorine = 3.38 mol
Explanation:
Given data:
Mass of chlorine = 120 g
Moles of chlorine = ?
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of chlorine = 35.5 g/mol
Now we will put the values in formula.
Number of moles = 120 g/ 35.5 g/mol
Number of moles = 3.38 mol
The formula for phosphorus is P4
