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Julli [10]
3 years ago
6

Now imagine that you are a haitian taptap driver and want a more comfortable ride. You decide to replace the springs with new sp

rings that can handle the typical heavy load on your vehicle. What spring constant do you want your new spring system to have?
Physics
1 answer:
Zinaida [17]3 years ago
4 0

k=  - f/x this is the formula for spring constants

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A current of 0.2 A flows through a conductor for 5minutes. How much charge would have passed through the conductor?​
Montano1993 [528]

As we know,

electric \:  \: current =  \dfrac{charge}{time}

so, let's solve for charge (q) :

time = 5 minutes = 5 × 60 seconds = 300 seconds.

  • 0.2 =  \dfrac{q}{300}

  • q = 300 \times 0.2

  • q = 60

hence, the charge = 60 coulombs (C)

4 0
3 years ago
I need to find the current resistance and voltage for each in this complicated circuit plz help
konstantin123 [22]

Explanation:

The 11Ω, 22Ω, and 33Ω resistors are in parallel.  That combination is in series with the 4Ω and 10Ω resistors.

The net resistance is:

R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)

R = 20Ω

Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:

V = IR

120 V = I (20Ω)

I = 6 A

So the voltage drops are:

V = (4Ω) (6A) = 24 V

V = (10Ω) (6A) = 60 V

That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:

V = 120 V − 24 V − 60 V

V = 36 V

So the currents are:

I = 36 V / 11 Ω = 3.27 A

I = 36 V / 22 Ω = 1.64 A

I = 36 V / 33 Ω = 1.09 A

If we wanted to, we could also show this using Kirchhoff's laws.

7 0
3 years ago
A baseball of mass m = 0.31 kg is spun vertically on a massless string of length L = 0.51m. The string can only support a tensio
natulia [17]

Given data:

* The mass of the baseball is 0.31 kg.

* The length of the string is 0.51 m.

* The maximum tension in the string is 7.5 N.

Solution:

The centripetal force acting on the ball at the top of the loop is,

\begin{gathered} T+mg=\frac{mv^2}{L}_{} \\ v^2=\frac{L(T+mg)}{m} \\ v=\sqrt[]{\frac{L(T+mg)}{m}} \end{gathered}

For the maximum velocity of the ball at the top of the vertical circular motion,

v_{\max }=\sqrt[]{\frac{L(T_{\max }+mg)}{m}}

where g is the acceleration due to gravity,

Substituting the known values,

\begin{gathered} v_{\max }=\sqrt[]{\frac{0.51(7.5_{}+0.31\times9.8)}{0.31}} \\ v_{\max }=\sqrt[]{\frac{0.51(10.538)}{0.31}} \\ v_{\max }=\sqrt[]{17.34} \\ v_{\max }=4.16\text{ m/s} \end{gathered}

Thus, the maximum speed of the ball at the top of the vertical circular motion is 4.16 meters per second.

8 0
1 year ago
How does the movement of particles of matter change when matter goes from solid to liquid? (1 point)
Y_Kistochka [10]

Answer: c

Explanation: because if it increases then it gets hotter

if it decreases then its getting colder.

3 0
2 years ago
The SI unit of refractive index is ___<br>a)km/s. b)m/s. c)sec. d)no unit​
cupoosta [38]

Answer:

d)no unit

Explanation:

refractive index is a unit less quantity.

6 0
3 years ago
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