PE = mgh
Mass, m = 7kg, g ≈ 10 m/s², height = 2m
= 7*10*2
= 140 Joules.
Answer:
a = 4.9(1 - sinθ - 0.4cosθ)
Explanation:
Really not possible without a complete setup.
I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g
F = ma
mg - mgsinθ - μmgcosθ = (m + m)a
mg(1 - sinθ - μcosθ) = 2ma
½g(1 - sinθ - μcosθ) = a
maximum acceleration is about 2.94 m/s² when θ = 0
acceleration will be zero when θ is greater than about 46.4°
Acceleration of the ball is 
Explanation:
The acceleration of the ball can be found by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

where
F is the net force
m is the mass
a is the acceleration
For the ball in this problem, we have
m = 0.50 kg (mass)
F = 25 N (force)
thereofre, the acceleration of the ball is

Learn more about Newton's second law:
brainly.com/question/3820012
#LearnwithBrainly
Answer:
Staying connected to friends
Explanation:
hope this helps
The change in distance is 30 because if you subtract both number you'll get 30