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san4es73 [151]
2 years ago
5

Select the parameters that are included in a baseline performance check. you may select more than one. select one or more: a. co

mpressor body temperature b. condenser fan rpm c. discharge pressure d. compressor amp draw e. suction pressure f. discharge line temperature previous page
Engineering
1 answer:
pishuonlain [190]2 years ago
6 0

Answer:

A F E C D B

Explanation:

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Cars, houses, Devices. :)
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3 years ago
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In , the industries with the most complaints to the Better Business Bureau were banks, cable and satellite television companies,
navik [9.2K]

Answer:

Answer for the question:

In , the industries with the most complaints to the Better Business Bureau were banks, cable and satellite television companies, collection agencies, cellular phone providers, and new car dealerships (USA Today, April 16, 2012). The results for a sample of complaints are contained in the DATAfile named BBB. Click on the datafile logo to reference the data."

is explained in the attachment.

Explanation:

Download pdf
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3 years ago
Determine (with justification) whether the following systems are (i) memoryless, (ii) causal, (iii) invertible, (iv) stable, and
lina2011 [118]

Answer:

a.

y[n] = x[n] x[n-1]  x[n+1]

(i) Memory-less - It is not memory-less because the given system is depend on past or future values.

(ii) Causal - It is non-casual because the present value of output depend on the future value of input.

(iii) Invertible - It is invertible and the inverse of the given system is \frac{1}{x[n] . x[n-1] x[n+1]}

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is not time invariant because the system is multiplying with a time varying function.

b.

y[n] = cos(x[n])

(i) Memory-less - It is memory-less because the given system is not depend on past or future values.

(ii) Causal - It is casual because the present value of output does not depend on the future value of input.

(iii) Invertible - It is not invertible because two or more than two input values can generate same output values .

For example - for x[n] = 0 , y[n] = cos(0) = 1

                       for x[n] = 2\pi , y[n] = cos(2\pi) = 1

(iv) Stable - It is stable because for all the bounded input, output is bounded.

(v) Time invariant - It is time invariant because the system is not multiplying with a time varying function.

3 0
2 years ago
Do all websites use the same coding to create?
Sonbull [250]

Answer:

yes.

Explanation:

because all websites use coding

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3 years ago
15 POINTS! Help.
IRISSAK [1]

Answer: it would  overload

Explanation:

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2 years ago
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