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Delicious77 [7]
3 years ago
12

What is substructure work?

Engineering
1 answer:
o-na [289]3 years ago
5 0
The answer is: Work below ground level.
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Guys, I need help. Describe carburetion as it applies to the four-stroke engine.
marta [7]

Answer:

(NH4)2Cr2O7→Cr2O3+N2+4H2O

Explanation:

(NH4)2Cr2O7→Cr2O3+N2+4H2O

7 0
3 years ago
Assume that a surface-grinding operation is being carried out under the following conditions: D = 250 mm, d 0.1 mm, ys 0.5 m/s a
Misha Larkins [42]

Answer:

modify temperature is lower than by the 0.196 %

Explanation:

given data

D = 250 mm

d = 0.1 mm

v = 0.5 m/s

V = 50 m/s

D = 150 mm

d = 0.1 mm

v = 0.3 m/s

V = 25 m/s

solution

first we get here initial coating condition for temperature change ΔT is

ΔT = A \times D^{1/4} \times d^{3/4}\times \frac{V}{v}^{1/2}    ...............1

put here value for both condition

ΔT = A \times 250^{1/4} \times 0.1^{3/4}\times \frac{50}{0.5}^{1/2}  

ΔT = 7.07 A      ......................2

and

ΔT = A \times 150^{1/4} \times 0.1^{3/4}\times \frac{25}{0.3}^{1/2}  

ΔT = 5.68 A       .......................3

so here percentage change is

percentage change = \frac{5.68 A-7.07 A }{7.07 A }  

percentage change  = - 0.196

so that modify temperature is lower than by the 0.196 %

5 0
3 years ago
You have been assigned the task of reviewing the relief scenarios for a specific chemical reactor in your plant. You are current
postnew [5]

Answer:

D=0.016m

Explanation:

From the question we are told that:

Discharge Rate F_r=0.5kgls

Pressure P=15Kpa

Temperature T=25=>298K

Ambient pressure is 1 atm.

Generally the equation for Density is mathematically given by

\rho=\frac{PM}{RT}

\rho=\frac{15*10^5*28.0134*10^{-3}}{8.314*298}

\rho=16.958kg/m^2

Generally the equation for Flow rate is mathematically given by

F_r=\mu A\sqrt{Q \rho P(\frac{2}{Q+1})^{\frac{Q+1}{Q-1}}}

Where

Q=Heat coefficient\ ratio\ of\ Nitrogen

Q=1.4

\mu= Discharge\ coefficient

\mu=0.68

Therefore

0.5=0.68 A\sqrt{1.4 16.958 15*10^{5}(\frac{2}{1.4+1})^{\frac{1.4+1}{1.4-1}}}

A=2.129*10^{-4}

Where

A=\frac{\pi}{4}D^2

\frac{\pi}{4}D^2=2.129*10^{-4}

D=0.016m

8 0
3 years ago
Can you prove that the two bleu areas are the same without numbers please?
Svet_ta [14]

Answer:

\small{\boxed{\tt{\colorbox{green}{✓Verified\:answer}}}}\:

Just draw a line from point D join to point E

The triangle formed DME will be congruent to AMC

6 0
3 years ago
If you had a match and a lantern and a candle in the dark which one would you choose to light.
PSYCHO15rus [73]

Answer:

The match

Explanation:

You can light both the lantern and the candle if you light the match first.

I don't know of this is a homework question, but I answered it anyway :)

5 0
4 years ago
Read 2 more answers
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