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dexar [7]
3 years ago
11

Which has a higher acceleration: a 10-kg object acted upon with a net force of 20 N or an 18-kg object acted on by a net force o

f 30 N?
A. Both accelerate at the same rate.

B. the 10-kg object

C. the 18-kg object
Physics
2 answers:
Montano1993 [528]3 years ago
6 0
The first one accelerate at 2m/s
the second one accelerates at 1.6666m/s

therefore statement b. the 10kg object is your answer

hope this helps :)
BaLLatris [955]3 years ago
4 0

Answer:

the answer is B, 10-kg object

Explanation:

Because of Newton we know that if a force is applied to an object, it will have an acceleration on the same direction of the force applied.

F=m*a\\\\where:\\m=mass\\a=acceleration

in order to obtain the acceleration we have to reordenate the formula:

a=\frac{F}{m}

The acceleration of the 10 kg object is:

a=\frac{20N}{10kg}=2\frac{m}{s^2}

The acceleration of the object of 18 kg is:

a=\frac{30N}{18kg}=1.67\frac{m}{s^2}

The biggest acceleration was for the object with less mass.

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An object with a mass of 78 kg is lifted through a height of 6 meters how much work is done
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We got the following:
m = 78kg
h = 6m
g = 9.8 m/sec^{2} ≈ 10 m/sec^{2}
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A = ?

As we know A = Ep = mgh    ->      potential energy
so the answer would be A = 78 * 6 * 10 = 4680 Joule


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Find the equivalent resistance, the current supplied by the battery and the current through each resistor when the specified res
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Answer:

R_{eq} = 19  Ω,   I = 0.105 A,   V1 = 1.05 V  and    V2 = 0.95 V

Explanation:

The correct way to solve this type of problem is to find the current or voltage values for the equivalent resistance and from here find the other values.

For a series circuit the equivalent resistance is the sum of the resistance

      R_{eq}= R1 + R2

       R_{eq} = 10 +9

       R_{eq} = 19  Ω

Let's use the equation for the voltage

     V = I R_{eq}

      I = V /  R_{eq}

      I = 2/19

      I = 0.105 A

In a series circuit the current is constant, so let's use the voltage equation for each resistor

     V1 = I R1

     V1 = 0.105 10

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