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dexar [7]
3 years ago
11

Which has a higher acceleration: a 10-kg object acted upon with a net force of 20 N or an 18-kg object acted on by a net force o

f 30 N?
A. Both accelerate at the same rate.

B. the 10-kg object

C. the 18-kg object
Physics
2 answers:
Montano1993 [528]3 years ago
6 0
The first one accelerate at 2m/s
the second one accelerates at 1.6666m/s

therefore statement b. the 10kg object is your answer

hope this helps :)
BaLLatris [955]3 years ago
4 0

Answer:

the answer is B, 10-kg object

Explanation:

Because of Newton we know that if a force is applied to an object, it will have an acceleration on the same direction of the force applied.

F=m*a\\\\where:\\m=mass\\a=acceleration

in order to obtain the acceleration we have to reordenate the formula:

a=\frac{F}{m}

The acceleration of the 10 kg object is:

a=\frac{20N}{10kg}=2\frac{m}{s^2}

The acceleration of the object of 18 kg is:

a=\frac{30N}{18kg}=1.67\frac{m}{s^2}

The biggest acceleration was for the object with less mass.

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A proton with charge 1.601019 As is moving at 2.4105 m/s through a magnetic field of 4.5 T. You want to find the force on the pr
Whitepunk [10]

The force on the proton is 17.4 N.

<h3>What is the force on the proton?</h3>

Now we know that the proton is positively charged and that the force on the charge as it moved through the magnetic field could be given by the relation; F = qvB

Where;

F = force

q = charge

v = velocity

B = magnetic field

Having said this, we can see that;

q = 1.601019 As or C

v =  2.4105 m/s

T = 4.5 T

F =  1.601019 As * 2.4105 m/s * 4.5 T

F = 17.4 N

Learn more about magnetic force:brainly.com/question/12824331

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6 0
2 years ago
An object on Earth weighs 150 N. What is its mass?
Alex777 [14]

Answer:

\tt \: mass \:  =  \frac{weight}{acceleration \: due \: to \: gravity}

\longrightarrow \tt \:  \frac{150}{10}

\longrightarrow \boxed{ \tt{15 \: kg}}

  • Our final answer is 15 kg .

----------- HappY LearninG<3 ------------

3 0
2 years ago
An athlete in a gym applies a constant force of 50 N to the pedals of a bicycle to keep the rotation rate of the wheel at 10 rev
marishachu [46]

Answer:

Explanation:

Given that,

Force applied to pedal F = 50N

Angular velocity ω = 10rev/s

We know that, 1rev = 2πrad

Then, ω = 10rev/s = 10×2π rad/s

ω = 20π rad/s

Length of pedal r = 30cm = 0.3m

Power?

Power is given as

P = τ×ω

We need to find the torque τ

τ = r × F

Since r is perpendicular to F

Then, τ = 0.3 × 50

τ = 15 Nm

Then,

P = τ×ω

P = 15 × 20π

P = 942.48 Watts

power delivered to the bicycle by the athlete is 942.48 W

6 0
3 years ago
Which part of the electromagnetic spectrum is divided into seven ranges of wavelengths and is the part visible to the human eye
oksano4ka [1.4K]
In one of the most amazing coincidences in all of science,
the part of the electromagnetic spectrum that's visible to the
human eye is called "visible light".

Visible light is not 'divided' into anything. We mention the names
to seven of the colors in visible light. But all of the thousands of
OTHER colors that we can see are in there too, even though we
don't bother to list their names when we buzz through the rainbow
in the third grade.
6 0
3 years ago
Read 2 more answers
The muzzle velocity of a rifle bullet is 709 m s−1along the direction of motion. If the bullet weighs 35 g, and the uncertainty
nydimaria [60]

Answer:

Uncertainty in position of the bullet is \Delta x=1.07\times 10^{-33}\ m

Explanation:

It is given that,

Mass of the bullet, m = 35 g = 0.035 kg

Velocity of bullet, v = 709 m/s

The uncertainty in momentum is 0.20%. The momentum of the bullet is given by :

p=mv

p=0.035\times 709=24.81\ kg-m/s

Uncertainty in momentum is,

\Delta p=0.2\%\ of\ 24.81

\Delta p=0.049

We need to find the uncertainty in position. It can be calculated using Heisenberg uncertainty principal as :

\Delta p.\Delta x\geq \dfrac{h}{4\pi}

\Delta x=\dfrac{h}{4\pi \Delta p}

\Delta x=\dfrac{6.62\times 10^{-34}}{4\pi \times 0.049}

\Delta x=1.07\times 10^{-33}\ m

Hence, this is the required solution.

7 0
3 years ago
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