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nadezda [96]
4 years ago
6

According to Kepler's Second Law the radius vector drawn from the Sun to a planet Multiple Choice is the same for all planets. s

weeps out equal areas in equal times. sweeps out a larger area for a given time when the planet is moving faster. sweeps out a larger area for a given time when the distance to the Sun is greater.
Physics
1 answer:
Mademuasel [1]4 years ago
4 0

Answer:

sweeps out equal areas in equal times.

Explanation:

As we know that there is no torque due to Sun on the planets revolving about the sun

so we will have

\tau_{net} = 0

now we have

\frac{dL}{dt}= 0

now we also know that

Area = \frac{1}{2}r^2d\theta

so rate of change in area is given as

\frac{dA}{dt} = \frac{1}{2}r^2\frac{d\theta}{dt}

so we will have

\frac{dA}{dt} = \frac{1}{2}r^2\omega

\frac{dA}{dt} = \frac{L}{2m}

since angular momentum and mass is constant here so

all planets sweeps out equal areas in equal times.

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A net force of 25N causes an object to accelerate at 4m/s^2. what is the mass of the object?
Doss [256]

Answer:

6.25 kg

Explanation:

Fnet=ma

m=Fnet/a

m=25/4

m=6.25kg

3 0
3 years ago
In your own words, discuss how tides are monitored. Describe the old and new methods of monitoring tides.
harkovskaia [24]
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6 0
4 years ago
Rita places a 2.5 kg block on a frictionless inclined plane that is 30 degrees above horizontal. She applies a horizontal force,
vitfil [10]

Answer:

14.2

Explanation:

find horizontal force of the weight = 2.5kg x 9.8 Sin30 = 12.3 N

to prevent the sliding she needs to pull horizontally

Fh = 12.3 /Cos 30 =14.2N

7 0
3 years ago
A blue car with mass mc = 427 kg is moving east with a speed of vc = 20 m/s and collides with a purple truck with mass mt = 1282
polet [3.4K]

Answer:8540 kg-g/s

Explanation:

Given

mass of blue car m_c=427 kg

velocity of blue car v_c=20 m/s

mass of the truck m_t=1282 kg

speed of truck v_t=13 m/s

After collision they stick and lock together

Let v be the velocity of combined system at angle \theta from vertical

Conserving momentum in east direction

m_c\times v_c=(m_c+m_t)v\cos \theta

427\times 20 =1709\times v\cos \theta------1

Conserving Momentum in Y direction

m_t\times v_t=(m_c+m_t)v\sin \theta

1282\times 13 =1709\times v\sin \theta-------2

squaring and then adding 1 & 2 we get

(8540)^2+(16666)^2=(1709)^2\cdot v^2

v=10.95 m/s

initial momentum of car=427\times 20=8540 kg-m/s

6 0
4 years ago
What electrons are in “motion”, what do you have?
Sergeeva-Olga [200]

Answer:

When a positive charged object is placed near a conductor electrons are attracted the the object. ... When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side. As you know, electrons are always moving. They spin very quickly around the nucleus of an atom. As the electrons zip around, they can move in any direction, as long as they stay in their shell.

7 0
4 years ago
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