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Schach [20]
3 years ago
13

What occurs when there are OH- ions in a solution?

Chemistry
1 answer:
Damm [24]3 years ago
7 0
What occures is that the solution is know considered to be alkali, OH- ions react with the H+ ions from acids.

hope that helps :)
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Which type of wave cannot move without a medium in which to travel?
Zanzabum

sound wave cannot travel without a medium.

5 0
2 years ago
Calculate the unit cell edge length for an 78 wt% Ag- 22 wt% Pd alloy. All of the palladium is in solid solution, and the crysta
BaLLatris [955]

Answer:

The unit cell edge length for the alloy is 0.405 nm

Explanation:

Given;

concentration of Ag, C_{Ag} = 78 wt%

concentration of Pd, C_P_d = 22 wt%

density of Ag = 10.49 g/cm³

density of Pd = 12.02 g/cm³

atomic weight of Ag, A_A_g = 107.87 g/mol

atomic weight of iron, A_P_d = 106.4 g/mol

Step 1: determine the average density of the alloy

\rho _{Avg.} = \frac{100}{\frac{C_A_g}{\rho _A_g} + \frac{C__{Pd}}{\rho _{Pd}} }

\rho _{Avg.} = \frac{100}{\frac{78}{10.49} + \frac{22}{12.02} } = 10.79 \ g/cm^3

Step 2: determine the average atomic weight of the alloy

A _{Avg.} = \frac{100}{\frac{C_v}{A _A_g} + \frac{C__{Pd}}{A _{Pd}} }

A _{Avg.} = \frac{100}{\frac{78}{107.87} + \frac{22}{106.4} } = 107.54 \ g/mole

Step 3: determine unit cell volume

V_c=\frac{nA_{avg.}}{\rho _{avg.} N_a}

for a FCC crystal structure, there are 4 atoms per unit cell; n = 4

V_c=\frac{4*107.54}{ 10.79*6.022*10^{23}} = 6.620*10^{-23} \ cm^3/cell

Step 4: determine the unit cell edge length

Vc = a³

a = V_c{^\frac{1}{3} }\\\\a = (6.620*10^{-23}}){^\frac{1}{3}}\\\\a = 4.05 *10^{-8} \ cm= 0.405 nm

Therefore, the unit cell edge length for the alloy is 0.405 nm

7 0
3 years ago
How did Rutherford’s atomic model fix the shortcomings of Thomson’s atomic model?
dedylja [7]

<u>Plum Pudding Model(Thomson's atomic model)</u>

  • Thomson's atomic model states that an atom has a positive sphere charge with electrons embedded inside it. He compared the atom with a plum pudding,as the electrons according to him seemed like the dry fruits embedded in the spherical pudding.

<u>Rutherford's Model</u>

  • However Rutherford bombarded high energy streams of α-particles on a thin gold foil of 100 nm thickness. The  deflection produced by  the trajectory of these high energy  α-particles after interaction with the thin sheet of gold was studied by placing a screen made up of zinc sulfide around the gold foil.
  • The major observations made by Rutherford were that  a very huge fraction of α-particles passed through the gold sheet without getting deflected. Thus he concluded that the major part of an atom must be empty.
  • Very few   α-particles  got deflected minutely or at very small angles  by the gold sheet when they were bombarded against it.  Also very few particles got deflected at large angles. This made him conclude that the positive charge is concentrated in a very small region and is  not distributed uniformly.

From the above observations he gave the following postulates:

  • An atom is made up of  positively charged particles. The mass of an atom was concentrated in small region which is  named as the nucleus of an atom.
  • The  nucleus is surrounded by  electrons which are negatively charged particles which  revolve around the nucleus in a fixed circular path called as “orbits.”
  • An atom is  electrically neutral because electrons are negatively charged and the  nucleus is positively charged. The electrons are held by the nucleus due to a  strong electrostatic force.
  • Compared to the total size of an atom the size of the nucleus is very small.
7 0
3 years ago
3
olga55 [171]

Answer:

D

Gratitude allows for a person to gain weight.

4 0
3 years ago
Read 2 more answers
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Alex Ar [27]
Hey there!

Static electricity is a missing charge. When positive ions are formed (where an electron is missing), this imbalance is called static electricity.

7 0
2 years ago
Read 2 more answers
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