The minimum mass of NaHCO3 that must be added to the spill to neutralize the acid is 27.216 grams
<h3>calculation </h3>
write the balanced chemical equation
2NaHCO3 +H2SO4 → Na2SO4 +2H2O +2CO2
find the moles of H2SO4 = molarity x volume in liters
volume in liters = 27/1000=0.027 l
moles is therefore= 0.027 x6=0.162 moles
by use of mole ratio of NaHCO3: H2SO4 which is 2:1 the moles of NaHCO3=0.162 x2=0.324 moles
mass of NaHCO3= moles of NaHCO3 x molar mass of NaHCO3(84g/mol)
= 84g/mol x 0.324=27.216 grams
Bc it waters the plants that provide for the fish
The particles will spread out more, and have more space between them
