If the hydrate gets too hot it could start splattering and cause a loss of sample.
Answer: 0.000625
Explanation:
If you don't know, one Milligram is equivalent to 0.000001 Kilograms. Hence, we'll multiply 625 by 0.000001.
With that being said, 625 times 0.000001 will equal to 0.000625.
Don't forget to add the units.
Milogram unit ⇒ mg
Kilogram unit ⇒ kg
Finally, your grand answer is 0.000625.
<em>Please comment down below for any questions about my answer.</em>
Answer:
b. 2 mol of KI in 500. g of water
Explanation:
We have to apply the colligative property of freezing point depression.
The formula is: ΔT = Kf . m . i
As the (Kf . m . i) is higher, then the freezing temperature will be lower.
i refers to the Van't Hoff factor (number of ions dissolved in the solution)
KI → K⁺ + I⁻ (i =2)
Kf is constant so, we have to search for the highest m (molality)
Molality means the moles of solute in 1kg of solvent.
The highest m is option b → 2 mol of KI / 0.5 kg = 4 mol/kg
a. 1 mol of KI / 0.5 kg = 2 mol/kg
c. 1 mol of KI / 1kg = 1 mol/kg
d. 2 mol of KI / 1kg = 2 mol/kg
1000 g = 1kg. In order to determine molality we need to convert the mass (g) of solvent to kg
Answer:
3.75 ml per dose
Explanation:
We need to convert the units from g to mg and then perform a cross-multiplication.
The concentration of the drug is 200 mg/ 5.0 ml
200 mg = 0.2 g (because 1 g equals 1000 mg)
x = 3.75 ml
