Answer:
The equilbrium constant is 179.6
Explanation:
To solve this question we can use the equation:
ΔG = -RTlnK
<em>Where ΔG is Gibbs free energy = 12.86kJ/mol</em>
<em>R is gas constant = 8.314x10⁻³kJ/molK</em>
<em>T is absolute temperature = 298K</em>
<em>And K is equilibrium constant.</em>
Replacing:
12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK
5.19 = lnK
e^5.19 = K
179.6 = K
<h3>The equilbrium constant is 179.6</h3>
C because I’m space there’s no gravity meaning things are weightless
Hydrogen and carbon because they are the most common element of canyon
The symbol of the radioactive nuclide, given the data is ⁴⁰₁₉K
<h3>Data obtained from the question</h3>
- Atomic number = 19
- Mass number = 40
- Symbol of nuclide =?
<h3>How to determine the nuclide</h3>
From the question given above, the atomic number of the nuclide is 19.
Comparing the atomic number (i.e 19) of the nuclide with those in the periodic table, the nuclide is potassium with a symbol of K
<h3>How to determine the symbol of the nuclide</h3>
- Atomic number (Z) = 19
- Mass number (A) = 40
- Name of nuclide = Potassium (K)
- Symbol of nuclide =?
The symbol of a nuclide is given as ᴬ₂X
Where
- A is the mass number
- Z is the atomic number
- X is the symbol of the element
Thus,
ᴬ₂X => ⁴⁰₁₉K
Therefore, the symbol of the nuclide is ⁴⁰₁₉K
Learn more about composition of atoms:
brainly.com/question/886387
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Answer:
Carbon Dioxide is an Infrared Radiation Absorber. The (CO2) molecules also emits the absorbed infrared (IR) radiation energy. The photon energy from the infrared radiation causes the CO2 molecule to vibrate. Only some of its vibrational modes absorb infrared radiation
Explanation:
Its linear structure is considered when working with the formula to calculate the number of molecular vibrational modes. It has 3n - 4 vibrational modes, where n is the number of atoms in a compound of CO2
With 3 atoms, CO2 has
3n−5=4 types or patterns of vibration
1. The symmetric stretch
2. The asymmetric stretch
3. The bend
The symmetric stretch vibrational mode is ir-inactive.
The asymmetric stretch is ir-active as it results in changes in dipole moment
The bend is ir-active as well as it results in a change in dipole moment too.
