Relative formula mass of ammonium sulphate?

Th e molar absorption coeffi cients of tryptophan and tyrosine at 240 nm are 2.00 × 103 dm3 mol−1 cm−1 and 1.12 × 104 dm3 mol−1

nataly862011 [7]

Answer:

5.43x10⁻⁵ dm³mol⁻¹= Concentration of tyrosine

2.58x10⁻⁵ dm³mol⁻¹= Concentration of tryptophan

Explanation:

Lambert-Beer law is:

A = E×C×l

Where A is measured absorbance, E is absorption coefficient, C is concentration of solution and l is optical path length.

For the result at 240nm, it is possible to write:

0.660 = 2.00x10³ dm³mol⁻¹cm⁻¹× Ctry × 1cm + 1.12x10⁴ dm³mol⁻¹cm⁻¹× Ctyr × 1cm (1)

At 280 nm:

0.221 = 5.40x10³ dm³mol⁻¹cm⁻¹× Ctry × 1cm + 1.50x10³ dm³mol⁻¹cm⁻¹× Ctyr × 1cm (2)

Thus:

-2.7× (0.660 = 2.00x10³ × Ctry + 1.12x10⁴ × Ctyr) =

-1.782 = -5.40x10³Ctry - 3.024x10⁴Ctyr

0.221 = 5.40x10³ × Ctry + 1.50x10³ × Ctyr

-------------------------------------------------------------------

-1.561 = -28740×Ctyr

5.43x10⁻⁵ dm³mol⁻¹= Ctyr

Replacing this value in (1) or (2) it is possible to find Ctry, that is:

2.58x10⁻⁵ dm³mol⁻¹= Ctry

4 0

3 years ago

!!HELP ASAP!!What is an electrostatic force?

lubasha [3.4K]

D. A force that acts between charged and uncharged particles. I think it’s D because the electrostatic force is the attractive or repulsive force between two electrically charged objects. D is the closest answer to the definition of electrostatic force

4 0

2 years ago

When a company is to calculate the selling price of their products, they set up a product calculation. There are five benefits t

iren [92.7K]

Answer:

The pricing strategy is an important element in setting up the selling price of a product.

Explanation:

The pricing strategy is an important consideration while fixing up the selling price of product manufactured. When setting up a selling price of a product, the companies set up product calculation. Businesses should decide the pricing strategy before they advertise the products to the customers.

There are mainly 5 benefits to the businesses while doing a product calculation. They are:

--- Doing competition based pricing enables the company to compete with the rival companies product and is based on the market based study. Competition pricing is a useful tool for the retailers as well as the small businesses.

--- Doing a cost plus pricing helps the total cost of making the product and also an add up in the market in order to determine the pricing of the product.

--- Dynamic pricing :

Dynamic pricing is a non static pricing. Dynamic pricing is an efficient method for the market based on the supply and demand.

--- Penetration pricing :

Penetration pricing is used by the large companies which is used to capture the market share by the setting product prices at the below market level so as to gain customers.

--- Doing a research for the price skimming helps the company to set up the accurate price for the product rather than readjusting the prices of the product later on based on the demand and the supply.

5 0

2 years ago

Why do larger gases such as Neon produce more color bands (line spectra) than smaller gases like Hydrogen?

LekaFEV [45]

Larger gases produces more spectral lines than the smaller gases because they have more orbitals in their atoms.
Hydrogen has only one orbital in which an electron orbits. At the excited state, that is, when the electron gains energy, the number of energy level it can transcend is very few. For larger elements, they have more orbitals and when excited, they can move from the ground state to other energy levels at which they produce various unique spectral lines.

7 0

2 years ago

The reaction described by H2(g)+I2(g)⟶2HI(g) has an experimentally determined rate law of rate=k[H2][I2] Some proposed mechanism

MatroZZZ [7]

Answer:

Mechanism A and B are consistent with observed rate law

Mechanism A is consistent with the observation of J. H. Sullivan

Explanation:

In a mechanism of a reaction, the rate is determinated by the slow step of the mechanism.

In the proposed mechanisms:

Mechanism A

(1) H2(g)+I2(g)→2HI(g)(one-step reaction)

Mechanism B

(1) I2(g)⇄2I(g)(fast, equilibrium)

(2) H2(g)+2I(g)→2HI(g) (slow)

Mechanism C

(1) I2(g) ⇄ 2I(g)(fast, equilibrium)

(2) I(g)+H2(g) ⇄ HI(g)+H(g) (slow)

(3) H(g)+I(g)→HI(g) (fast)

The rate laws are:

A: rate = k₁ [H2] [I2]

B: rate = k₂ [H2] [I]²

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]

Where K' = K1 * K2

C: rate = k₁ [H2] [I]

As:

K-1 [I]² = K1 [I2]:

rate = k' [H2] [I2]^1/2

Thus, just mechanism A and B are consistent with observed rate law

In the equilibrium of B, you can see the I-I bond is broken in a fast equilibrium (That means the rupture of the bond is not a determinating step in the reaction), but in mechanism A, the fast rupture of I-I bond could increase in a big way the rate of the reaction. Thus, just mechanism A is consistent with the observation of J. H. Sullivan

5 0

2 years ago