Answer:
Given that
The earth spins on its axis once a day and orbits the sun once a year (365 1/4 days)
a)
When earth spins on its axis
We know that earth take 1 day to complete one revolution around its own axis.
T= 1 day = 24 hr = 24 x 3600 s
T=86400 s
We know that
T=2π/ω
ω= 2π/T
ω= 2π/86400
ω=7.27 x 10⁻5 rad/s
b)
When earth revolve around earth
T =365 1/4 days = 365.25 days
T= 365.24 x 86400 s
T=31557600
We know that
T=2π/ω
ω= 2π/T
ω= 2π/31557600
ω=1.99 x 10⁻⁷ rad/s
Answer:
The impuise is 7.9905 kg*m/s
Explanation:
Step one:
given data
v1= +2.63m/s
v2=-20.2m/s
mass m= 0.350kg
Step two:
From the expression for impulse
Ft= mΔv
substituting our data into the expression we have
Ft= 0.35*(-20.2-2.63)
Ft= 0.35*22.83
Ft=7.9905 kg*m/s
I'm pretty sure the answer is B: <span>establish public doubt
Hope this helps!</span>
