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snow_lady [41]
3 years ago
5

A concise definition of pair production

Physics
1 answer:
kogti [31]3 years ago
6 0
Pair production<span> is a direct conversion of radiant energy to matter. It is one of the principal ways in which high-energy gamma rays are absorbed in matter. </span>
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How much thermal energy is
Alex17521 [72]

Answer:

Qt = 940500 [J]

Explanation:

In order to solve this problem and understand it well, we must analyze that the ice melts or changes phase at a temperature of 0 [°c], then the water at a temperature of 100 [°C] evaporates or changes phase. That is, we have 5 different stages of water (initially in the form of ice), which are:

-) From -30 [°C] to 0 [°C] = Sensible change of temperature

-) At 0 [°C] = Latent heat of melting ice = 334 x 10³ [J/kg]

-) From 0 [°C] to 100 [°C] = Sensible change of temperature

-) At 100 [°C] = Latent heat of fusion for water = 2260 x 10³ [J/kg]

-) From 100 [°C] to 130 [°C] = Sensible change of temperature (superheating)

We can calculate the sensible heat of any process with the following expression:

Q=m*C_{p}*(T_{f}-T_{i})

where:

Q = heat or thermal energy [J]

m = mass of the body or substance = 300 [g]

Cpw = specific heat of the water = 4180 [J/kg*°C]

Cpi = specific heat of the ice = 2090 [J/kg*°C]

Tfinal = final temperature of the process [°C]

Tinicial = initial temperature of the process [°C]

And for some latent heat process, we can calculate the thermal energy using the following expression:

Q_{lat}=m*Dh_{fus/eva}

where:

Dhfus/eva = Fusion heat or latent heat [J/kg]

So, we need to calculate the fice processes.

Q_{1}=0.3*2090*(0-(-30))\\Q_{1}=18810 [J]\\Q_{2}=0.3*334*10^{3} \\Q_{2}=100200[J]\\Q_{3}=0.3*4180*(100-0)\\Q_{3}=125400[J]\\Q_{4}=0.3*2260*10^{3}\\Q_{4}=678000[J]\\Q_{5}=0.3*2010*(130-100)\\Q_{5}=18090[J]

And the final step is the sum of all the five heat processes.

Q_{t}=Q_{1}+Q_{2}+Q_{3}+Q_{4}+Q_{5}\\Q_{t}=18810+100200+125400+678000+18090\\Q_{t}=940500[J]

8 0
2 years ago
What is the difference between solar minimum and solar maximum
LekaFEV [45]

Answer:

In any specified solar cycle, the highest number of sunspots is referred to as "solar maximum." The lowest number is referred as "solar minimum."

Explanation:

Around every 11 years, the sun passes through a  solar cycle. The cycle is defined by increasing and decreasing sunspots— noticeable on a sun's surface as dark imperfections, or photosphere.

In any specified solar cycle, the highest number of sunspots is referred to as "solar maximum." The lowest number is referred as "solar minimum." The latest solar minimum was obtained in 2008

6 0
3 years ago
Consider the uniform electric field \vec{E} =(4.00~\hat{j}+3.00~\hat{k})\times 10^3~\text{N/C} ​E ​⃗ ​​ =(4.00 ​j ​^ ​​ +3.00 ​k
Tema [17]

Answer:

Electric flux, \phi=6.668\times 10^4\ Nm^2/C

Explanation:

It is given that,

Electric field, E=(4j+3k)\times 10^3\ N/C

We need to find the electric flux through a circular area of radius 2.66 m that lies in the xy-plane. A=Ak

The electric flux is given by :

\phi=E{\cdot}A

\phi=(4j+3k)\times 10^3{\cdot}Ak

Since, k.k=i.i=j.j = 1

So,

\phi=3\times 10^3\times \pi\times (2.66)^2\ k

\phi=6.668\times 10^4\ Nm^2/C

So, the electric flux through a circular area is \phi=6.668\times 10^4\ Nm^2/C.Hence, this is the required solution.

6 0
3 years ago
What is the average velocity of atoms in 1.00 mol of neon (a monatomic gas) at 465 K? For m, use 0.0202 kg.
TiliK225 [7]

Answer: 757m/s

Explanation:

Given the following :

Mole of neon gas = 1.00 mol

Temperature = 465k

Mass = 0.0202kg

Using the ideal gas equation. For calculating the average kinetic energy molecule :

0.5(mv^2) = 3/2 nRt

Where ;

M = mass, V = volume. R = gas constant(8.31 jK-1 mol-1, t = temperature in Kelvin, n = number of moles

Plugging our values

0.5(0.0202 × v^2) = 3/2 (1 × 8.31 × 465)

0.0101 v^2 = 5796.225

v^2 = 5796.225 / 0.0101

v^2 = 573883.66

v = √573883.66

v = 757.55109m/s

v = 757m/s

5 0
3 years ago
a pool ball leaves a 0.60-meter high table with an initial high table with an initial horizontal velocity of 2.4m/s. what is the
inysia [295]

Answer:

0.84 m

Explanation:

Given in the y direction:

Δy = 0.60 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

0.60 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 0.35 s

Given in the x direction:

v₀ = 2.4 m/s

a = 0 m/s²

t = 0.35 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (2.4 m/s) (0.35 s) + ½ (0 m/s²) (0.35 s)²

Δx = 0.84 m

5 0
3 years ago
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