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katrin2010 [14]
3 years ago
7

In a 30.0-s interval, 500 hailstones strike a glass window with an area of 0.600m2 at an angle of 45.0°to the window surface. Ea

ch hailstone has a mass of 5.00g and a
speed of 8.00 m/s. If the collisions are elastic, what are the average force and pressure on the window?
Physics
1 answer:
aliina [53]3 years ago
5 0

or one hailstone we have;
Force = Mass X acceleration = 0.005kg x 9.8.} This is when the hailstone is not inclined at an angle.
When the hailstone is inclined at an angle of 45, then the component of force along the glass window will be F =0.005kg x 9.8 x sin45= 0.005kg x 9.8 x 0.707= 0.0346N.
Therefore, total force for the 500 hailstones would be 500x0.0346N=17.32N
This force is acting on an area equal to 0.600m2
Pressure = Force per unit area = 17.32N/0.600m2 = 28.9Pa

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Three bulbs are connected by tubing, and the tubing is evacuated. The volume of the tubing is 45.0 mL. The first bulb has a volu
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Answer:

The final pressure of the whole system is 34.80 atm.

Explanation:

Given that,

Volume = 45.0 ml

Volume of first bulb = 77.0 mL

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Pressure = 2.82 atm

Volume of third  bulb = 21.0 mL

Pressure = 8.42 atm

We need to calculate the final pressure of the whole system

Using formula of pressure

P_{1}V_{1}+P_{2}V_{2}+P_{3}V_{3}+P_{t}V_{t}=P_{f}V_{f}

Where, P_{1}= pressure of first bulb

P_{2}= pressure of second bulb

P_{3}= pressure of third bulb

P_{4}= initial pressure of tube

V_{1}= Volume of first bulb

V_{2}=Volume of second bulb

V_{3}= Volume of third bulb

V_{4}= Initial volume of tube

Put the value into the formula

8.89\times77.0+250\times2.82+21.0\times8.42+0=P_{f}\times45

P_{f}=\dfrac{1566.35}{45}

P_{f}=34.80\ atm

Hence, The final pressure of the whole system is 34.80 atm.

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3 years ago
The position of a ball as a function of time is given by
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Answer:

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Explanation:

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We need to find the position of the ball at 1.9 s. It can be simply calculated putting t = 1.9 s in equation (1) as :

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So, the position of the ball at 1.9 seconds is -6.5 meters. Hence, this is the required solution.

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This new research question would help you find out if there is an already existing mask that could be made better.

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