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katrin2010 [14]
3 years ago
7

In a 30.0-s interval, 500 hailstones strike a glass window with an area of 0.600m2 at an angle of 45.0°to the window surface. Ea

ch hailstone has a mass of 5.00g and a
speed of 8.00 m/s. If the collisions are elastic, what are the average force and pressure on the window?
Physics
1 answer:
aliina [53]3 years ago
5 0

or one hailstone we have;
Force = Mass X acceleration = 0.005kg x 9.8.} This is when the hailstone is not inclined at an angle.
When the hailstone is inclined at an angle of 45, then the component of force along the glass window will be F =0.005kg x 9.8 x sin45= 0.005kg x 9.8 x 0.707= 0.0346N.
Therefore, total force for the 500 hailstones would be 500x0.0346N=17.32N
This force is acting on an area equal to 0.600m2
Pressure = Force per unit area = 17.32N/0.600m2 = 28.9Pa

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As you stand near a railroad track, a train passes by at a speed of 31.7 m/s while sounding its horn at a frequency of 218 Hz. W
Darya [45]

Explanation:

Given that,

Frequency of train horn, f = 218 Hz

Speed of train, v_t = 31.7 m/s

The speed of sound, V = 344 m/s (say)

The speed of the observed person, V_o=0\ m/s

(a) When the train approaches you, the Doppler's effect gives the frequency as follows :

f'=f(\dfrac{V}{V-v_t})\\\\f'=218\times (\dfrac{344}{344-31.7})\\\\f'=240.12\ Hz

(b) When the train moves away from you, the Doppler's effect gives the frequency as follows :

f'=f(\dfrac{V}{V+v_t})\\\\f'=218\times (\dfrac{344}{344+31.7})\\\\f'=199.6\ Hz

Hence, this is the required solution.

6 0
3 years ago
A wrench 20 cm long lies along the positive y-axis and grips a bolt at the origin. A force is applied in the direction 0, 4, −3
Andreyy89

Answer:

1250 N

Explanation:

length of wrench = 20 cm = 0.2 m

Write the length of wrench in vector form

r = 0.2 j metre

Direction of force= \frac{0i+4j-3k}{\sqrt{0 + 16 + 9}}=\frac{0i+4j-3k}{5}

Let the magnitude of force is F

So, write the force in vector form

F = F  \frac{0i+4j-3k}{\sqrt{0 + 16 + 9}}=\frac{0i+4j-3k}{5}

torque, T = 150 Nm

Torque = T = r x F

150 i =0.2j\times F\frac{0i+4j-3k}{5}

F = 1250 N

Thus, the magnitude of force is 1250 N.

6 0
3 years ago
Two glass marbles (1 and 2), each supported by a nylon thread, are rubbed against a piece of silk and then are placed near a thi
iragen [17]

Answer:

d.) Marbles 1 and 2 repel each other, but no interaction occurs with marble

Explanation:

Rubbing the glass against the silk charges the glass positively.

Assuming polarization is ignored,

●Glass won't conduct electrical charge. Therefore, acting as a insulator.

●neutral objects won't distribute it's charge when affected by charge objects in proximity. Therefore, over the marble surface, the charge remain spherically symmetrical (undisturbed)

Marble 1 is positive

Marble 2 is positive

Since marble 1 and 2 are positive, repulsion will occur.

marble 3 is neutral (still assuming polarization is ignored), therefore, no interaction with marble 1 and 2

D is the answer.

4 0
3 years ago
An object is placed 50.0 cm in front of a convex mirror. where can be the image located if the focal length is 40 cm from the mi
sergiy2304 [10]

Answer:

Image will form at distance 22.22 cm behind the mirror

Explanation:

As we know that the mirror formula is given as

\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}

now we know that

object distance from mirror is

d_o = -50 cm

Focal length of the mirror is given as

f = 40 cm

now we have

\frac{1}{-50} + \frac{1}{d_i} = \frac{1}{40}

\frac{1}{d_i} = \frac{1}{50} + \frac{1}{40}

d_i = 22.22 cm

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Harlamova29_29 [7]

Answer:d

Explanation:

4 0
2 years ago
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