A 76-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 840 N. What is the acceleration
1 answer:
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Answer:
21 m
Explanation:
The motion of the frog is a uniform motion (constant speed), therefore we can find the distance travelled by using
where
d is the distance covered
v is the speed
t is the time
The frog in this problem has a speed of
v = 2.1 m/s
and therefore, after t = 10 s, the distance it covered is
Answer:
1.81×10^-4Io
Explanation:
Check attachment
Answer:
The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.
The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.
Explanation:
The net calorific value is equal to the heat produced (), in kilojoules, divided by the mass of the burnt fuel (
). We proceed to calculate the net calorific value of each fuel:
Fuel 1 (,
)
The net calorific value of the fuel 1 is 40000 kilojoules per kilogram.
Fuel 2 (,
)
The net calorific value of the fuel 2 is 50000 kilojoules per kilogram.