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Step2247 [10]
3 years ago
14

A 76-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 840 N. What is the acceleration

of the elevator? 1.25 Correct: Your answer is correct. m/s2 upward
Physics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

1.25 m/s^2

Explanation:

m = 76 kg, R = 840 N

Let a be the acceleration of teh elevator in upward direction.

By use of Newton's second law

R - mg = m a

R = m ( g + a)

840 = 76 ( 9.8 + a)

a = 1.25 m/s^2

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you travel an average speed of 20 km/h in a straight line to get to your grandmothers house. it takes you 3 hours to get to her
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6.6 miles I think hope this is the right answer.
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3 years ago
A steam stream of 400 m3 /s, standard (standard cubic meter per second) is cooled by adding 7 m3 /s cold water. The fluid leavin
antiseptic1488 [7]

Answer: 510 m/s

Explanation: specific gravity of steam is 18/29 = 0.620

It is the ratio of the density of steam over density of water

400m3/s of steam =

400m3ms * 0.620 of water

= 248m3/s of water

Total flow rate Q = 248 + 7 = 255m3/s

Using Q = AV

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4 0
3 years ago
1. Spring force is proportional to stretch distance, F=kd. Do you expect doubling the stretch distance double the force?
Solnce55 [7]

Answer:

Yes

Explanation:

The spring force is given as:

          F  = kd

F is the spring force

K is the spring constant

d is the magnitude of the stretch

 Since k is a constant, therefore, doubling the stretch distance will double the force.

Both stretch distance and force applied can be said to be directly proportional to one another.

3 0
3 years ago
A wooden block of mass m = 9 kg starts from rest on an inclined plane sloped at an angle θ = 30° from the horizontal. The block
jenyasd209 [6]

Answer:

Fk = 21.645N

Explanation:

Let Fb be Force of block and thus;

Fb= mg where m is mass of block and g is acceleration due to gravity

Thus Fb= 9kg x 9.81N/kg = 88.29 N

Now, the question says this force Fb rests at an inclined plane [email protected] 30° angle

Thus;

Force parallel to inclined plane = 88.29 x sin30° = 44.145 N.

Force perpendicular to the inclined plane = 88.29 x cos30 = 76.46 N

Now, when an object is falling freely, we know that

h = (1/2)at^(2)

From the question, the height is 5m and t= 2 seconds

Thus;

5 = (1/2)a(2)^(2)

2a = 5 and thus,

a = 5/2 = 2.5 m/s^(2)

Now, in inclined planes, perpendicular force - kinetic friction force = Resultant force

Thus let perpendicular be Fp and kinetic friction force be Fk and so;

Fp - Fk = F

F= ma = 9 x 2.5 = 22.5N

Thus, 44.145 - Fk = 22.5

Thus, Fk = 44.145 - 22.5 = 21.645N

5 0
3 years ago
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