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Step2247 [10]
3 years ago
14

A 76-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 840 N. What is the acceleration

of the elevator? 1.25 Correct: Your answer is correct. m/s2 upward
Physics
1 answer:
vovikov84 [41]3 years ago
8 0

Answer:

1.25 m/s^2

Explanation:

m = 76 kg, R = 840 N

Let a be the acceleration of teh elevator in upward direction.

By use of Newton's second law

R - mg = m a

R = m ( g + a)

840 = 76 ( 9.8 + a)

a = 1.25 m/s^2

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Someone pls review my work
Darya [45]

In astronomy, Johannes Kepler published his three laws about planetary motion. It is one of the most important things in astronomy. So Kepler gives three laws about planetary motion.

<h3>What is motion?</h3>

Motion is a physical term in physics. If a particle of mass m and affected by some force F then it change its position in many different way. That is the motion of the object. It is a vector quantity.

<h3>What is Kepler's three laws?</h3>

In astronomy, Johannes Kepler published his three laws about planetary motion between 1609 and 1619. This shows about motion describe the orbits of planets around the Sun. So the three motions are shown following,

<u>First law</u>: Every planet in solar system that moves in a elliptical orbits where the sun always in the center of the motion.

<u>Second law</u>: Every planet covers the same amount of distance in a constant time no matter where the orbit of the planet placed. That means the velocity of every planet is not same. It varies along with the orbit. But every time the change of area is constant.

<u>Third law</u>: The orbital period of the planet is proportional with the cube of the semi major axis of the planet. It can be shown mathematically,

p²∝a³

Where we know,

p= The orbital period of the planet.

a= the semi major axis of the planet.

From the discussion we can easily shown that there are three laws of Kepler about planetary motion.

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#SPJ13

6 0
11 months ago
Calculate the average time it took the car to travel 0. 25 and 0. 50 meters with three washers attached to the pulley. Record th
EastWind [94]

The Speed of a moving vehicle can be measured. The average time it will taken too cover both distance are shown below;

The average travel times traveled are :

0.25 meters = 2.23 seconds

0.50 meters = 3.13 seconds

Therefore, the Average travel time to cover 0.25 meters is:

(Trial 1 + Trial 2 + Trial 3) ÷ 3

(2.24 + 2.21 + 2.23) / 3 = 6.68 = 2.2266 = 2.23 seconds ( approximated to 2 decimal places).

Therefore, the Average travel time to cover 0.50 meters is

(Trial 1 + Trial 2 + Trial 3) ÷ 3

(3.16 + 3.08 + 3.15) / 3 = 9.39 ÷ 3 = 3.13 seconds

Conclusively, the average time taken to cover 0.25 and 0.50 meters is said to be 2.23 and 3.13 seconds for the both..

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brainly.com/question/25738530

6 0
2 years ago
At the top of a giant swing on the gymnastics high bar, candy's velocity is 1 m/s, and she is 3.5 m high. if candy's mass is 50
Allushta [10]
The total mechanical energy is the sum of the kinetic energy and the gravitational potential energy:
E=K+U= \frac{1}{2}mv^2 +mgh
where m=3.5 kg is Candy's mass, v=1 m/s is her velocity and h=3.5 m is her height. If we replace these numbers, we find the mechanical energy of the system:
E= \frac{1}{2} (50 kg)(1m/s)^2 + (50 kg)(9.81 m/s^2)(3.5 m)=1742 J =1.74 kJ
6 0
3 years ago
The radius of a small ball is around 3.79747 cm. The radius of a basketball is about 3.16 times larger. What is the ratio of the
Svetradugi [14.3K]

Explanation:

The ratio of the areas is the square of the ratio of the radii.

A/A = 3.16² = 9.99

The ratio of the volumes is the cube of the ratio of the radii.

V/V = 3.16³ = 31.6

3 0
3 years ago
A 3.90 kg block is in equilibrium on an incline of 31.0◦. The acceleration of gravity is 9.81 m/s2 . What is Fn of the incline o
storchak [24]

Answer:

Explanation:

The sum of the pore along the plane is expressed according to Newton's law

Fn-Ff = ma

Fn is the moving force

Ff = nR = frictional force

m is the Mass

a is the acceleration

Substitute the given values

Fn - nR = ma

Fn - tan31°(mgcostheta) =3.9(9.8)

Fn - tan31(3.9(9.8)cos31) = 3.9(9.8)

Fn - tan31(38.22cos31)= 38.22

Fn - 32.76tan31 = 38.22

Fn-19.68 = 38.22

Fn = 38.22+19.68.

Fn = 57.90N

Hence Fn (moving force) of the inclined block is 57.90

4 0
3 years ago
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