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vaieri [72.5K]
2 years ago
10

What is the velocity of the object at 20.0s

Physics
1 answer:
Korvikt [17]2 years ago
5 0
So notice that at the beginning of the motion, the object moves to 16m in a span of about 10 seconds. You should know that the velocity in a pvt graph is the slope, so here the v = 1.6 m/s more or less. At 20 seconds, the object doesn't seem to be moving and you see it stays still from 10-26ish seconds. From observing you can tell that there is no velocity, but the slope of this segment is zero so you can be sure of it. 
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A -0.06 charge that moves downward is in a uniform electric field with a strengthened of 200 N/C. What is the magnitude and dire
Nookie1986 [14]

Answer:

The magnitude of the force is 12 N Upwards

Explanation:

The force on a positive charge will be in the same direction as the field, but the force on a negative charge will be in the opposite direction to the field. Thus the direction of the force is upward.

Given;

magnitude of charge, q = 0.06 C

magnitude of electric field, E = 200 N/C

The magnitude of the force is given by;

F = qE

F = 0.06 x 200 N/C

F = 12 N Upwards

Therefore, the magnitude of the force is 12 N Upwards

5 0
3 years ago
4. What are 3 things that you can think of doing, that would reduce<br> your electricity bill?
Cloud [144]
Turn off standby appliances.
Install a smart thermostat.
Turn down your thermostat.
Buy efficient appliances.
Install a new boiler.
Wash clothes at a lower temperature.
Be smarter about water.
Invest in double glazing.
3 0
2 years ago
How much energy ( in joules ) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature ?
aleksley [76]

Answer:

B. 17,705.1 J

Explanation:

The hear released when the mercury condenses into a liquid is given by:

Q=m \lambda_v

where

m = 0.06 kg is the mass of the mercury

\lambda_v is the latent heat of vaporization

For mercury, the latent heat of vaporization is \lambda_v = 296 kJ/kg, so the heat released during the process is:

Q=(0.06 kg)(296 kJ/kg)=17.76 kJ = 17,760 J

So, the closest option is

B. 17,705.1 J

5 0
3 years ago
Read 2 more answers
A lamp in a child's Halloween costume flashes based on an RC discharge of a capacitor through its resistance. The effective dura
pshichka [43]

Answer:

A. 0.199 J

B. 0.0663 C

C = 0.0221 F

D. 12.68 ohms

Explanation:

From the question:

time duration, t = 0.28 seconds

Average power, P = 0.71 W

Average voltage, V = 3 V

A) Energy is given as:

E = P * t

=> E = 0.71 * 0.28 = 0.199 J

B) Electrical energy is also given as:

E = qV

where q = charge

=> q = E / V

∴ q = 0.199 / 3 = 0.0663 C

C) Capacitance is given as charge over voltage:

C = q / V

=> C = 0.0663 / 3 = 0.0221 F

D) Electrical power, P, can also be given as:

P = V^2 / R

where R = resistance

=> R = V^2 / P

R = 3^2 / 0.71 = 9 / 0.71 = 12.68 ohms

8 0
2 years ago
Sandra wanted to see how fast she could kick a soccer ball. She recorded her results below. Unfortunately, she forgot to record
alexira [117]
Kick | Distance (M) | Time (s) | Average Speed

1. 55. 5.0. 11

2. 50. 5.0. 10

3. 20. 3.0. 10
5 0
2 years ago
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