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serg [7]
4 years ago
9

2) If the current in any circuit reach to infinity then its resistance becomes

Physics
1 answer:
sveta [45]4 years ago
3 0

Given that,

Current = ∞

We know that,

Ohm's law :

Ohm's law is defined as,

The voltage of the circuit is directly proportional to the current of the circuit.

V\propto I

Or,

The voltage of the circuit is equal to the product of current and resistance.

In mathematically,

V=IR

Where, V = voltage

I = current

R = resistance

According to ohm's law,

The current in the circuit is

I=\dfrac{V}{R}

If the current is very less then the resistance will be infinity.

If the is reach to infinity then the resistance will be very low.

Hence, The resistance becomes very low.

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Write about Archimedes principle​
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How many newtons of force will 2 pieces of paper have if one has a charge of .2 Coilombs and the other has a charge of .3 Coulom
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1) The electrostatic force between the two pieces of paper is 2.16\cdot 10^{13} N

2)

  • If the charges of the two pieces of paper are both + or both -, they repel each other
  • If the charges of one piece of paper is positive and the other one is negative, they attract each other

Explanation:

1)

The electrostatic force between two charged objects is given by Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where:

k=8.99\cdot 10^9 Nm^{-2}C^{-2} is the Coulomb's constant

q_1, q_2 are the two charges

r is the separation between the two charges

In this problem, we have the following situation:

q_1 = 0.2 C is the charge on the first piece of paper

q_2 = 0.3 C is the charge on the second piece of paper

r=0.005 m is their separation

Substituting into the equation, we find the magnitude of the electrostatic force between them:

F=k\frac{q_1 q_2}{r^2}=(8.99\cdot 10^9) \frac{(0.2)(0.3)}{(0.005)^2}=2.16\cdot 10^{13} N

2)

The electrostatic force can be either attractive of repulsive, depending on the relative sign of the charges of the objects involved.

In particular, we have:

  • If the two charges have same sign (both positive or both negative), the force between them is repulsive
  • If the two charges have opposite sign (one positive and one negative), the force between them is attractive

Therefore, in this case:

  • If the charges of the two pieces of paper are both + or both -, they repel each other
  • If the charges of one piece of paper is positive and the other one is negative, they attract each other

Learn more about electric force:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

7 0
4 years ago
A student calculates the density of a copper cube to be 4.15 g/cm . If the accepted value is 8.64 g/cm the percentage error in h
Helen [10]

 The percentage error in his experimental value is -51.97%.

<h3>What is percentage error?</h3>

This is the ratio of the error to the actual measurement, expressed in percentage.

To calculate the percentage error of the student, we use the formula below.

Formula:

  • Error(%) = (calculated value-accepted value)100/(accepted............. Equation 1

From the question,

Given:

  • Calculated value = 4.15 g/cm
  • accepted value = 8.64 g/cm

Substitute these values into equation 1

  • Error(%) = (4.15-8.64)100/8.64
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  • Error(%) = -449/8.64
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Hence, The percentage error in his experimental value is -51.97%.

Learn more percentage error here: brainly.com/question/5493941

8 0
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