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xz_007 [3.2K]
3 years ago
13

How does insulin bind to cells and the mechanism involved in triggering the cells to take in glucose

Chemistry
1 answer:
Lera25 [3.4K]3 years ago
7 0

Explanation:

Once blood glucose levels increase, pancreatic insulin migrates into a fat cell via the blood stream. Insulin then binds in the plasma membrane of the cell to an Insulin Receptor (IR). Through autophosphorylation, phosphate groups are then added to the IR,  causing GLUT4 molecules to come to the cell's surface.

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Assessment
MakcuM [25]

i didn’t mean to put this opps

4 0
3 years ago
As the concentration of a KOH solution increases, the number of moles of HCl needed to neutralize the KOH solution?
Soloha48 [4]

B) increasesAnswer:

Explanation:

8 0
3 years ago
if 11.74 liters of gas at STP are pumped into a basketball, how many moles of gas are in the basketball? assume the basketball w
ser-zykov [4K]

Answer:

0.52 mol

Explanation:

Using the general gas equation formula:

PV = nRT

Where;

P = pressure (atm)

V = volume (Liters)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

At STP (standard temperature and pressure), temperature of a gas is 273K, while its pressure is 1 atm

Using PV = nRT

n = PV/RT

n = (1 × 11.74) ÷ (0.0821 × 273)

n = 11.74 ÷ 22.41

n = 0.52 mol

There are 0.52 moles in the basketball

6 0
3 years ago
Which kind of investigations allow for the control of variables?
Butoxors [25]

Answer:

the answer to this is O hypothesis

5 0
3 years ago
How many milliliters of 4.00 M NaOH are required to exactly neutralize 50.0 milliliters of a 2.00 M solution of HNO3 ?
kramer

Answer: The volume of NaOH required is 25.0 ml

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity HNO_3 = 1

M_1 = molarity of HNO_3 solution = 2.00 M

V_1 = volume of  HNO_3 solution = 50.0 ml

n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 4.00 M

V_1 = volume of  NaOH solution =  ?

Putting in the values we get:

1\times 2.00\times 50.0=1\times 4.00\times V_2

V_2=25.0ml

Therefore, volume of NaOH required is 25.0 ml

3 0
3 years ago
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