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xz_007 [3.2K]
4 years ago
13

How does insulin bind to cells and the mechanism involved in triggering the cells to take in glucose

Chemistry
1 answer:
Lera25 [3.4K]4 years ago
7 0

Explanation:

Once blood glucose levels increase, pancreatic insulin migrates into a fat cell via the blood stream. Insulin then binds in the plasma membrane of the cell to an Insulin Receptor (IR). Through autophosphorylation, phosphate groups are then added to the IR,  causing GLUT4 molecules to come to the cell's surface.

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What is the maximum number of electrons found in any energy level of the known elements? (Refer to the periodic table.)
Simora [160]

Answer:

2n^2 electrons

Explanation:

for example, the first level contain 2*(1^2) = 2 electrons, the second level contain 2*(2^2) = 8 electrons, etc

5 0
3 years ago
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What is the heat of reaction (AH) of the<br> following?<br> C(s) + O2 (g) --&gt; CO2 (g)
zlopas [31]

Answer:

C co2 2co enthalpy

2 Answers. Ernest Z. The standard enthalpy of formation of carbon monoxide is -99 kJ/mol.

8 0
4 years ago
At what point in time (A ,B or C) is the reaction the fastest? How do you know?
gladu [14]
Don’t click that link EVER, they try to use your camera fsr
4 0
3 years ago
23 grams of Acetaminophen is equal to how many moles?
larisa86 [58]

Answer:

0.15215407

Explanation:

Im not 100% sure if this is correct!

5 0
3 years ago
Water (10 kg/s) at 1 bar pressure and 50 C is pumped isothermally to 10 bar. What is the pump work? (Use the steam tables.) O -7
11Alexandr11 [23.1K]

Explanation:

For an isothermal process equation will be as follows.

                W = nRT ln\frac{P_{1}}{P_{2}}

It is given that mass is 10 kg/s or 10,000 g/s (as 1 kg = 1000 g). So, calculate number of moles of water as follows.

                    No. of moles = \frac{mass}{\text{molar mass}}

                                           = \frac{10000 g/s}{18 g/mol}

                                           = 555.55 mol/s

                                           = 556 mol/s (approx)

As T = 50^{o}C or (50 + 273.15) K = 323.15 K. Hence, putting the given values into the above formula as follows.

                  W = nRT ln[/tex]\frac{P_{1}}{P_{2}}[/tex]

                      = 556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times ln\frac{1}{10}    

                     = 556 mol/s \times 8.314 J/ K mol K \times 323.15 K \times -2.303    

                     = -3440193.809 J/s

Negative sign shows work is done by the pump. Since, 1 J = 0.001 kJ. Therefore, converting the calculated value into kJ as follows.

                     3440193.809 J/s \times \frac{0.001 kJ}{1 J}

                          = 3440.193 kJ/s

                          = 3451 kJ/s (approx)

Thus, we can conclude that the pump work is 3451 kJ/s.

6 0
4 years ago
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