Different radioactive nuclides decay into their respective daughter nuclides at distinct rates. Some of the nuclides decay briskly, while others decay gradually. The time it consumes for half of the parent nuclide in a radioactive sample to decay to the daughter nuclides is known as the half-life of the radioactive sample.
The nuclides, which decay briskly exhibit short half-lives and are very active. The half-life can be utilized to find the rates of radioactive decay. In the given question, the half-lives of various nuclides are given. So, the order to the most active (shortest half-life or largest number of decays per second) to least reactive (largest half-life or the smallest number of decays per second) is:
Tc-99m > Y-90 > In-111 > I-131
Answer:
Yes
Explanation:
Standard temperature and pressure conditions are defined as 1 atm pressure and 273.15 K. On the other hand, standard ambient temperature and pressure conditions are defined as 1 atm pressure and 298.15 K.
Notice, however, that the only change between them is in temperature.
In any standard conditions, the standard atmospheric pressure is equal to 1 atm.
At sea level, the atmospheric pressure is also equal to 1 atm.
Therefore, we may conclude that the standard atmospheric pressure is equivalent to the normal air pressure at sea level. With an increase in altitude, however, the atmospheric pressure decreases.
Answer:
449.5 g
Explanation:
Silver sulfate- Ag2SO4
M(Ag)=107 g/mol => M(Ag2)=214 g/mol
M(S)=32 g/mol
M(O)=16 g/mol => M(O4)=64 g/mol
M(Ag2SO4)=310 g/mol
n=1.45 mol
m(Ag2SO4)=M(Ag2SO4)*n=310 g/mol *1.45 mol= 449.5 g
2.11x10^24 Ca atoms
In order to find the amount of atoms we must use Avogadro’s number, 6.022 x 10^23
Since we have moles, 3.5 the equation would look like this
3.5 moles Ca x 6.022x10^23/1 = 2.1077 x 10^24, which we round to 2.11 x 10^24 atoms of Ca
Ionization is a formation of ions from neutral atoms or molecules.
SO₂ + H₂O = HSO₃⁻ + H⁺
Mg(OH)₂ = Mg²⁺ + 2OH⁻
