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andre [41]
4 years ago
8

An archeologist finds a 1.62 kg goblet that she believes to be made of pure gold. She determines that the volume of the goblet i

s 205 mL. How to calculate the density?
Chemistry
2 answers:
Sveta_85 [38]4 years ago
6 0

Answer : The density of goblet is 7.902 g/mL

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used :

Density=\frac{Mass}{Volume}

Given :

Mass of goblet = 1.62 kg = 1620 g

conversion used : (1 kg = 1000 g)

Volume of goblet = 205 mL

Now put all the given values in the above formula, we get:

Density=\frac{1620g}{205mL}=7.902g/mL

Therefore, the density of goblet is 7.902 g/mL

maxonik [38]4 years ago
3 0
Density (d) which is the quotient when mass (m) is divided by volume (v) is usually reported in terms of g/mL. 
                                  d = m /v
Substituting the known values,
                                d = (1.62 kg) x (1000 g/ 1 kg) / (205 mL)
The answer would be approximately equal to 7.9 g/mL. 
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Most jet fuel has an average molecular formula of C13H28 and a density of 804 g/L. Calculate the moles of carbon that are releas
aleksandr82 [10.1K]

Answer:

Number of moles = 558.46 mol

Explanation:

Density = 804 g/L

Molecular formula = C13H28

Molar mass = 184.37 g/mol

Distance = 3680 km

Rate = 3.48 L of fuel per 100. km

Volume is calculated as follow;

3.48 = 100

x = 3680

x = 3680 * 3.48 / 100

x = 128.064 L

Number of moles = Mass / Molar mass

Mass = Density *  Volume

Mass = 804 * 128.064 = 102963.456 g

Number of moles = 102963.456 / 184.37

Number of moles = 558.46 mol

7 0
3 years ago
Which properties do not change the composition of a substance?
Nina [5.8K]

Answer:

Physical Properties

Explanation:

PHYSICAL PROPERTY

7 0
4 years ago
The combination of water and CO2 molecules in the atmosphere account for approximately 155 W/m^2 in greenhouse heating.
lorasvet [3.4K]

Answer:

the final temperature is T=305.63 K

Explanation:

using the Stephan-Boltzmann equation for black bodies

q = σ*(T⁴-T₀⁴)

where

q= heat flux = 155 W/m²+150 W/m² = 255 W/m²

σ= Stephan-Boltzmann constant = 5.67*10⁻⁸ W/m²K⁴

T= absolute temperature

T₀= absolute initial temperature = 255 K

solving for T

q = σ*(T⁴-T₀⁴)

T = (q/σ + T₀⁴)^(1/4)

replacing values

T = (q/σ + T₀⁴)^(1/4) = (255 W/m²/(5.67*10⁻⁸ W/m²K⁴) + (255 K)⁴)^(1/4) = 305.63 K

T=305.63 K

thus the final temperature is T=305.63 K

7 0
4 years ago
I need help with #2. I don't know what law to use for problem.
bagirrra123 [75]
This uses something called the combined gas law. The combined gas law is as follows: (P1*V1/T1) = (P2*V2/T2)
According to question 2, you are given the following values initially:
P1 = 680 mm Hg * (1 atm/760 mm Hg) = 0.895 atm
V1 = 20.0 L
T1 = 293 K
STP or standard temperature and pressure implies that the other values we know are:
P2 = 1 atm
T2 = 273 K
Our unknown is V2
If we plug in our known values into the combined gas law:
(P1*V1/T1) = (P2*V2/T2)
(0.895 atm * 20.0 L)/293K = (1 atm * X liters)/273 K
0.0611 L*atm/K = (1 atm * X liters)/273 K
16.7 L = X liters
Therefore, the volume occupied at STP is 16.7 liters
This makes sense because the gas would occupy a smaller volume at a lower temperature, since the gas would have a lower average kinetic energy.
 
4 0
3 years ago
What do scientists use to increase the surface area of a solute
marta [7]

use a mortar & pestle to grind the solute into smaller particles, thus increasing the surface area.


6 0
4 years ago
Read 2 more answers
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