Find the t-value such that the area in the right tail is 0.2 with 5 degrees of freedom.

1 answer:

3 0

Answer:

0.920

Step-by-step explanation:

To calculate this, we proceed to the t-table

Using degree of freedom 5 and significance level of 0.2, the t-value is 0.920

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ale4655 [162]

Answer:

f(x) = -5/9 x + 5 1/9

Step-by-step explanation:

f(2)=4 and f(−7)=9 means the line pass through (2,4) and (- 7,9)

f(x) = mx + b

m = (y-y') / (x-x') = (9 - 4) / (- 7 - 2) = - 5/9

for (2,4) : b = f(x) - mx = y - mx = 4 - (- 5/9) x 2 = 4 + 10/9 = 46/9 = 5 1/9

f(x) = -5/9 x + 5 1/9

check for (-7, 9) f(-7) = (-5/9) * (-7) + 5 1/9 = 35/9 + 46/9 = 81/9 = 9

5 0

3 years ago

Colt1911 [192]

Answer:

99.7% of customers have to wait between 8 minutes to 30 minutes for their food.

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 18 minutes

Standard Deviation, σ = 4 minutes

We are given that the distribution of amount of time is a bell shaped distribution that is a normal distribution.

Empirical Formula:

Almost all the data lies within three standard deviation from the mean for a normally distributed data.
About 68% of data lies within one standard deviation from the mean.
About 95% of data lies within two standard deviations of the mean.
About 99.7% of data lies within three standard deviation of the mean.

Thus, 99.7% of the customers have to wait:

$\mu -3\sigma = 18-3(4) = 6\\\mu +3\sigma = 18+3(4) = 30$