Answer:
The tangential speed of the tack is 6.988 meters per second.
Explanation:
The tangential speed experimented by the tack (), measured in meters per second, is equal to the product of the angular speed of the wheel (), measured in radians per second, and the distance of the tack respect to the rotation axis (), measured in meters, length that coincides with the radius of the tire. First, we convert the angular speed of the wheel from revolutions per second to radians per second:
Then, the tangential speed of the tack is: (, )
The tangential speed of the tack is 6.988 meters per second.
Answer: Sound Energy
Sound Energy
Explanation:The vibrations produced by the ringing bell causes waves of pressure that travel or propagate through the medium that is air. Sound energy is a form of mechanical energy that is generally associated with the motion and position of the ringing bell.
Answer:
3000 newton force is required
Explanation:
F = ma
F= 1000 kgs x 3 m/s^ 2
F=3000(kgs x m/s^2)
F=3000 newton
Answer:
increase, GPE, KE, KE, KE, PE, PE, KE, KE,
Explanation:
Answer: 2.37N
Explanation:
According to coulombs law which states that the force of attraction (F) between two charges (q1 and q2) is directly proportional to the product of their charges and inversely proportional to the square of the distance (r) between them. Mathematically,
F = kq1q2/r²
For the first two charges that are sitting 1.5 m apart with a force of 3 N between them, we have
3 = kq1q2/1.5²
3 = kq1q2/2.25
Kq1q2= 6.75... (1)
If the charges are now moved farther apart 2.25 m and one of the charges is increased by a factor of 4. The formula becomes
F2 = k(4q1)q2/2.25² (q1 has been increased by factor of 4)
k(4q1)q2 = 5.06F2 ... (2)
Dividing 2 by 1 we have
k(4q1)q2/kq1q2 = 5.06F2/3
4 = 5.06F2/3
5.06F2 = 12
F2= 12/5.06
F2 = 2.37N
Therefore the magnitude of the new force between the two charges is 2.37N