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2 years ago

11

Both physical and chemical changes are accompanied by a change in the total energy of the system, which is divided into two broa

d categories, ____ energy due to motion and ___ energy due to position

1 answer:

olga2289 [7]2 years ago

8 0

Answer:

I believe <u>kinetic / potential</u>

Explanation:

You might be interested in

A metal block has a density of 5000 kg per cubic meter and a mass of 15,000 kg. What is its volume?

Naily [24]

Taking into account the definition of density, the volume of the metal block is 3 m³.

<h3>What is density</h3>

Density is defined as the property that matter, whether solid, liquid or gas, has to compress into a given space.

In other words, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance.

Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:

$density=\frac{mass}{volume}$

From this expression it can be deduced that density is inversely proportional to volume: the smaller the volume occupied by a given mass, the higher the density.

<h3>Volume of the metal block</h3>

In this case, you know that:

Density= 5000 $\frac{kg}{m^{3} }$
Mass= 15000 kg
Volume= ?

Replacing in the definition of density:

$5000 \frac{kg}{m^{3} } =\frac{15000 kg}{volume}$

Solving:

volume×5000 $\frac{kg}{m^{3} }$ = 15000 kg

volume= $\frac{15000 kg}{5000 \frac{kg}{m^{3} }}$

<u><em>volume= 3 m³</em></u>

In summary, the volume of the metal block is 3 m³.

Learn more about density:

brainly.com/question/952755

brainly.com/question/1462554

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4 0

2 years ago

imagine that two balls, a basketball and a much larger exercise ball, are dropped from a parking garage. If both the mass and ra

tiny-mole [99]

Hypothesis

Let there is no air drag or any other resistance force due to surrounding

Now the force equation of ball is given as

$F = mg$

$ma = mg$

$a = g$

so the ball will be dropped down by acceleration a = g and this acceleration is independent of size and mass of the ball

So in this case both balls will be dropped by same acceleration.

So here both balls will hit the ground at same time

4 0

3 years ago

a bullet moving with a velocity of 100m/s pierce a block of wood and moves out with a velocityof 10 m/s.if the thickness of the

erma4kov [3.2K]

The emerging velocity of the bullet is <u>71 m/s.</u>

The bullet of mass <em>m</em> moving with a velocity <em>u</em> has kinetic energy. When it pierces the block of wood, the block exerts a force of friction on the bullet. As the bullet passes through the block, work is done against the resistive forces exerted on the bullet by the block. This results in the reduction of the bullet's kinetic energy. The bullet has a speed <em>v</em> when it emerges from the block.

If the block exerts a resistive force <em>F</em> on the bullet and the thickness of the block is <em>x</em> then, the work done by the resistive force is given by,

$W=Fx$

This is equal to the change in the bullet's kinetic energy.

$W=Fx=\frac{1}{2} m(u^2-v^2)......(1)$

If the thickness of the block is reduced by one-half, the bullet emerges out with a velocity v<em>₁.</em>

Assuming the same resistive forces to act on the bullet,

$F(\frac{x}{2} )=\frac{1}{2} m(u^2-v_1^2)......(2)$

Divide equation (2) by equation (1) and simplify for v<em>₁.</em>

$\frac{\frac{Fx}{2} }{Fx} =\frac{(u^2-v_1^2)}{(u^2-v^2)} \\\frac{100^2-v_1^2}{100^2-10^2} =\frac{1}{2} \\v_1^2=5050\\v_1=71.06 m/s$

Thus the speed of the bullet is 71 m/s

3 0

3 years ago

3. Which of the following is true about astronauts taking out the TRASH?

scoray [572]

Answer:

C

Explanation:

When trash accumulates, astronauts manually squeeze it into trash bags, temporarily storing almost two metric tons of it for relatively short durations, and then send it away in a departing commercial supply vehicle, which either returns it to Earth or incinerates it during reentry through the atmosphere.

6 0

3 years ago

A 1325 kg car and a 2050 kg pickup truck approach a curve on a highway that has a radius of 255 m. At what angle should the high

Scorpion4ik [409]

Answer:

the banking angle of the road is 24.2⁰

Explanation:

Given;

speed of the vehicles considered, v = 75 mi/h

Speed in m/s ⇒ 1 mi/h --------> 0.44704 m/s

75 mi/h --------> ?

= 75 x 0.44704 m/s = 33.528 m/s

radius of the curve, r = 255 m

The banking angle of the road is calculated as;

$\theta = tan^{-1} (\frac{v^2}{rg} )\\\\\theta = tan^{-1} (\frac{33.528^2}{255\times 9.8} )\\\\\theta = tan^{-1}(0.44983)\\\\\theta =24.2^0$

Therefore, the banking angle of the road is 24.2⁰

8 0

3 years ago