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nikitadnepr [17]
3 years ago
11

WILL MARK AS BRAINLIEST!!!!!!

Physics
1 answer:
yaroslaw [1]3 years ago
4 0

M1V1 + M2V2 = M1V1' + M2V2'

where:

M1 is the mass of the large marble = 0.05 kg

V1 is the initial velocity of the large marble = 0.6 m/sec

M2 is the mass of the small marble = 0.03 kg

V2 is the initial velocity of the small marble = 0 m/sec (marble is at rest)

V1' is the final velocity of the large marble = -0.2 m/sec

V2' is the final velocity of the small marble that we want to calculate

Substitute with the givens in the above equation to get V2' as follows:

M1V1 + M2V2 = M1V1' + M2V2'

(0.05)(0.6) + (0.03)(0) = (0.05)(-0.2) + 0.03V2'

0.03 = -0.01 + 0.03V2'

0.03V2' = 0.03+0.01 = 0.04

V2' = 0.04/0.03

V2' = 1.334 m/sec

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disa [49]

Answer:

1.67 A

Explanation:

Given that,

→ Power (P) = 400 W

→ Potential difference (V) = 240 V

→ Current (I) = ?

The amount of current drawn will be,

→ P = V × I

→ I = P/V

→ I = 400/240

→ I = 1.66666666667

→ [ I = 1.67 A ]

Hence, the current drawn 1.67 A.

8 0
2 years ago
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Based on their colors, which of the following stars is hottest? Which is coolest? Archenar (blue), Betelgeuse (red), Capella (ye
Cloud [144]

Answer: The hottest star is Archenar( blue) and the coolest star is Betelgeuse

Explanation:

Objects emit radiation that depends exclusively on their temperature. At an ambient temperature, the radiation emitted by an object is in the infrared spectrum (we could only see it with a special camera). If we heat it we will see that it first turns red (whose state we call “red hot”) because it is the lowest and least energetic wavelength of all.

If we continue to heat it, the wavelength that it emits to one with more energy will continue to increase and we will see that it turns yellow and then white. This is a signal that is emitting at all frequencies (but mainly in blue).

If we continue to warm a body that is "white hot", it would emit in the ultraviolet spectrum, with what would become ... black! then we would not see it emits light in the visible spectrum (well, we would see a very faint bluish light corresponding to the tail of the distribution of the spectrum it emits, but the peak of that spectrum would be in the ultraviolet).

6 0
3 years ago
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Which of the following is/are true? Electromagnetic waves are created by accelerating charges. Electromagnetic waves are transve
Vikki [24]

Answer:

All of the above are true.

Explanation:

(a). true  

whenever  charge particle  move back and froth from its mean position then it will produce oscillating electric and magnetic fields, . so an em wave can be obtain by accelerating charge

(b). true

the electric field and the magnetic field have vibrations in the perpendicular direction along  the motion of the wave  so electromagnetic wave is a transverse wave. therefore, the EM wave is a Transverse wave

(c) true .

The Electromagnetic wave consists of the two mutually perpendicular electric and magnetic fields  and also both fields are  perpendicular to the direction of propagation of the wave.

(d) true .

An electromagnetic wave  carry  energy through  vacuum with a speed   of 3 \times 10^8 m/s  

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4 0
3 years ago
An object traveling 200 feet per second slows to 50 feet per second in 5 seconds. Calculate the acceleration of the object. Use
shtirl [24]

Answer:

-30m/s

Explanation:

Given:

Initial velocity of object  = 200 feet/second

Final velocity of object  = 50 feet/second

Time of travel = 5 seconds

To calculate acceleration of the object we will find the rate of change of velocity with respect to time.

So, acceleration "a" is given by:

a=\frac{v_f-v_i}{t}

where vf represents final velocity, vi represents initial velocity and  is time of travel.

Plugging in values to evaluate acceleration.

a=\frac{50-200}{5}

a=\frac{-150}{5}

a= -30m/s

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3 0
3 years ago
An ordinary egg can be approximated as a 5.5-cm diameter sphere. The egg is initially at a uniform temperature of 8°C and is dro
kupik [55]

Answer:

a) Q_{in} = 13.742\,kW, b) \Delta S = 370.15\,\frac{kJ}{K}

Explanation:

a) The heat transfered to the egg is computed by the First Law of Thermodynamics:

Q_{in} +U_{sys,1} - U_{sys,2} = 0

Q_{in} = U_{sys,2} - U_{sys,1}

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Q_{in} = \left(1020\,\frac{kg}{m^{3}}\right)\cdot \left(\frac{4\pi}{3}\right)\cdot (0.025\,m)^{3}\cdot \left(3.32\,\frac{kJ}{kg\cdot ^{\textdegree}C} \right)\cdot (70\,^{\textdegree}C - 8\,^{\textdegree}C)

Q_{in} = 13.742\,kW

b) The amount of entropy generation is determined by the Second Law of Thermodynamics:

\Delta S = \frac{Q_{in}}{T_{in}}

\Delta S = \frac{13.742\,kJ}{370.15\,K}

\Delta S = 370.15\,\frac{kJ}{K}

3 0
3 years ago
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