Answer:
for the reaction
is -108kJ
Explanation:
The balanced chemical reaction is,
The expression for enthalpy change is,
![\Delta H=[n\times B.E_{reactants}]-[n\times B.E{products}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5Bn%5Ctimes%20B.E_%7Breactants%7D%5D-%5Bn%5Ctimes%20B.E%7Bproducts%7D%5D)
where, n = number of moles
Now put all the given values in this expression, we get
![\Delta H=[1\times B.E_{Cl_2}+1\times B.E_{F_2}]-[2\times B.E_{ClF}]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B1%5Ctimes%20B.E_%7BCl_2%7D%2B1%5Ctimes%20B.E_%7BF_2%7D%5D-%5B2%5Ctimes%20B.E_%7BClF%7D%5D)
![\Delta H=[(1\times 243)+(1\times 159)]-[2\times 255]](https://tex.z-dn.net/?f=%5CDelta%20H%3D%5B%281%5Ctimes%20243%29%2B%281%5Ctimes%20159%29%5D-%5B2%5Ctimes%20255%5D)

Thus
for the reaction
is -108kJ
gravity
Explanation:
gravity is the same in any planet
Answer:
The mass percent of aluminum sulfate in the sample is 16.18%.
Explanation:
Mass of the sample = 1.45 g

Mass of the precipitate = 0.107 g
Moles of aluminum hydroxide = 
According to reaction, 2 moles of aluminum hydroxide is obtained from 1 mole of aluminum sulfate .
Then 0.001372 moles of aluminum hydroxide will be obtained from:

Mass of 0.000686 moles of aluminum sulfate :
= 0.000686 mol × 342 g/mol = 0.2346 g
The mass percent of aluminum sulfate in the sample:

Answer:
b) 2.0 mol
Explanation:
Given data:
Number of moles of Ca needed = ?
Number of moles of water present = 4.0 mol
Solution:
Chemical equation:
Ca + 2H₂O → Ca(OH)₂ + H₂
now we will compare the moles of Ca and H₂O .
H₂O : Ca
2 : 1
4.0 : 1/2×4.0 = 2.0 mol
Thus, 2 moles of Ca are needed.
Answer :]
to convert from g NaOH to mol NaOH. = 1.48 g NaOH are needed to neutralize the acid.