Answer:
See explanation
Explanation:
Given:
Initial pressure,
p
1
=
15
psia
Initial temperature,
T
1
=
80
∘
F
Final temperature,
T
2
=
200
∘
F
Find the gas constant and specific heat for carbon dioxide from the Properties Table of Ideal Gases.
R
=
0.04513
Btu/lbm.R
C
v
=
0.158
Btu/lbm.R
Find the work done during the isobaric process.
w
1
−
2
=
p
(
v
2
−
v
1
)
=
R
(
T
2
−
T
1
)
=
0.04513
(
200
−
80
)
w
1
−
2
=
5.4156
Btu/lbm
Find the change in internal energy during process.
Δ
u
1
−
2
=
C
v
(
T
2
−
T
1
)
=
0.158
(
200
−
80
)
=
18.96
Btu/lbm
Find the heat transfer during the process using the first law of thermodynamics.
q
1
−
2
=
w
1
−
2
+
Δ
u
1
−
2
=
5.4156
+
18.96
q
1
−
2
=
24.38
Btu/lbm
Answer:d
Explanation:
(d) chain drive belt drive gear drive
Answer:
180 x 60 inches
Width = 60 inches
Length = 180 inches
Explanation:
Given
Let L = Length
W = Width
P = Perimeter
Length = 3 * Width
L = 3W
Perimeter of Brass = 480 inches
P = 480
Perimeter is given as 2(L + W);
So, 2 (L + W) = 480
L + W = 480/2
L + W = 240
Substitute 3W for L; so,
3W + W = 240
4W = 240
W = 240/4
W = 60 inches
L = 3W
L = 3 * 60
L = 180 inches
An o ring intended for use in a hydraulic system using MIL-H-5606 (mineral base) fluid will be marked with a blue stripe or dot.
