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Dmitrij [34]
3 years ago
7

If a 5.00-minute shower requires 85.0 L of water, how much water would you save if you shortened

Chemistry
1 answer:
Slav-nsk [51]3 years ago
4 0

Answer:

12.75 liters.

Explanation:

By proportion that would be  (300 - 45/ 300) * 85 = 72.25 liters you would use.

So you save 85 - 72.25 liters.

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The first step in HNO3 production is the catalyzed oxidation of NH3. Without a catalyst, a different reaction predominates:
alexira [117]

Answer:

Kc = 6x10⁻⁶

Explanation:

For the reaction:

4NH₃(g) + 3O₂(g) ⇄ 2N₂(g) + 6H₂O(g)

Kc is defined as:

Kc =[N₂]² [H₂O]⁶ / [NH₃]⁴ [O₂]³

The equilibrium concentrations of the gases is -Because volume of the container is 1.00L-:

[N₂] = 2X = 1.96x10⁻³; <em>X = 9.8x10⁻⁴</em>

[H₂O] = 6X; 6ₓ9.8x10⁻⁴ = 5.88x10⁻³

[NH₃] = 0.0150M - 4X = 0.01108M

[O₂] = 0.0150M - 3X = 0.01206M

Replacing in Kc expression:

Kc =[1.96x10⁻³]² [5.88x10⁻³]⁶ / [0.01108M]⁴ [0.01206M]³

<h3>Kc = 6x10⁻⁶</h3>

8 0
4 years ago
WS 3.5 more Lewis structures
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6 0
3 years ago
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Knowing that the distances the truck traveled during each segment were 30, 45, 50, and 65 respectively, what was the total dista
stich3 [128]

Answer:

Total\ Distance = 190

Explanation:

Given

Distance = \{30, 45, 50, 65\}

Required

Determine the total distance

This is calculated by summing up the distance in each segment.

Total\ Distance = 30 + 45 + 50 + 65

Total\ Distance = 190

4 0
3 years ago
11. A sample contains 25% water and weighs 201 grams. Determine the grams of water in the
77julia77 [94]

Answer:

m_{water}=50.25g

Explanation:

Hello,

In this case, considering that the by-mass percent of water is:

\% m/m=\frac{m_{water}}{m_{sample}}*100\%

Given such percent and the mass of the sample, we can find the mass of water in grams in the sample by solving for it as shown below:

m_{water}=\frac{\%m/m*m_{sample}}{100\%}\\ \\m_{water}=\frac{25\%*201g}{100\%}\\ \\m_{water}=50.25g

Best regards.

5 0
3 years ago
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