Answer:
9.17 atm
Explanation:
To find the new pressure of the gas, you need to use the following manipulated formula:
P₁V₁ / T₁ = P₂V₂ / T₂
In this formula,
P₁ = initial pressure (atm) P₂ = new pressure (atm)
V₁ = initial volume (L) V₂ = new volume (L)
T₁ = initial temperature (K) T₂ = new temperature (K)
Because you have been given values for all of the variables except for the new pressure, you can substitute them into the equation and simplify.
P₁ = 4.0 atm P₂ = ? atm
V₁ = 5.5 L V₂ = 2.0 L
T₁ = 300 K T₂ = 250 K
P₁V₁ / T₁ = P₂V₂ / T₂ <----- Given formula
(4.0 atm)(5.5 L) / (300 K) = P₂(2.0 L) / (250 K) <----- Insert variables
0.073333 = P₂(2.0 L) / (250 K) <----- Simplify left side
18.33333 = P₂(2.0 L) <----- Multiply both sides by 250
9.17 = P₂ <----- Divide both sides by 2.0
Answer:
wer
c=3.00×108 m/s (the speed of light in a vacuum) λ = wavelength in meters ν = frequency in Hertz (Hz) or 1s or s−1 .
Explanation:
I might be wrong also you don't have to give me brainliest save it for someone else who knows I might be wrong
<span>What caused the bubbles to form when you added the catalyses to the hydrogen peroxide and water mixture at 40 °C? A. Catalyses activity heated the solution to its boiling point. B. Hydrogen gas formed during the formation of hydrogen peroxide. C. Oxygen gas formed during the decomposition of hydrogen peroxide.
This would be the water, mixture.</span>
Explanation:
Here are the answers. Do note that I had to convert the enthalpy to joules and temperature to Kelvin to make the unit for entropy work out.
Oxygen,hydrogen, and carbon