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3 years ago

How many grams are equivalent to 1.80x10-4 tons?

Chemistry

1 answer:

zloy xaker [14]3 years ago

6 0

Do you want the estimated answer or the exact answer?

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Astatine, At, is below iodine in Group 17 of the Periodic Table. Which statement is most likely to be correct?

Sphinxa [80]

The answer is A hope this helps

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2 years ago

A gas sample occupies 200 mL at 760 mm Hg. What volume does the gas occupy at 400 mm Hg?

astra-53 [7]

Answer:

201.9

Explanation:

when you divided 760 with 400 yo get 19.0 the add it with 200 you get that answer

3 0

3 years ago

For the reaction 2 H2S(g) D 2 H2 (g) + S2 (g), Kp = 1.5 × 10−5 at 800.0°C. If the initial partial pressures of H2 and S2 in a cl

Usimov [2.4K]

Answer: The approximate equilibrium partial pressure of $H_2S$ is 3.92 atm

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

The given balanced equilibrium reaction is,

$2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)$

$K_p=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

$1.5\times 10^{-5}=\frac{[H_2]^2\times [S_2]}{[H_2S]^2}$

On reversing the reaction:

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

initial pressure 4.00atm 2.00 atm 0

eqm (4.00-2x)atm (2.00-x) atm 2x atm

$K_p=\frac{[H_2S]^2}{[H_2]^2\times [S_2]}$

$K_p'=\frac{1}{K_p}=0.67\times 10^5$

$2H_2(g)+S_2(g)\rightleftharpoons 2H_2S(g)$

$0.67\times 10^5=\frac{2x]^2}{[4.00-2x]^2\times [2.00-x]}$

$x=1.96$

$[H_2S]=2x=2\times 1.96=3.92 atm$

Thus approximate equilibrium partial pressure of $H_2S$ is 3.92 atm

3 0

3 years ago

What occurs after cytokinesis is completed at the end of meiosis I?

arlik [135]

Answer. After cytokinesis is completed at end of meiosis - I two haploid cells are formed.on:

5 0

2 years ago

At 1000 K, Kp=19.9 for the reaction Fe2O3(s)+3CO(g)<--->2Fe(s)+3CO2(g) What are the equilibrium partial pressures of CO an

SOVA2 [1]

Answer: The equilibrium concentration of CO is 0.243 atm

Explanation:

We are given:

Initial partial pressure of carbon dioxide = 0.902 atm

As, carbon dioxide is present initially. This means that the reaction is proceeding backwards.

For the given chemical equation:

$Fe_2O_3(s)+3CO(g)\rightleftharpoons 2Fe(s)+3CO_2(g)$

Initial: 0.902

At eqllm: 3x (0.902-3x)

The expression of $K_p$ for above equation follows:

$K_p=\frac{(p_{CO_2})^3}{(p_{CO})^3}$

We are given:

$K_p=19.9$

Putting values in above equation, we get:

$19.9=\frac{(0.902-3x)^3}{(3x)^3}\\\\x=0.0810$

So, equilibrium concentration of CO = 3x = (3 × 0.0810) = 0.243atm[/tex]

Hence, the equilibrium concentration of CO is 0.243 atm

6 0

3 years ago

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