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sweet-ann [11.9K]
4 years ago
14

How many grams are equivalent to 1.80x10-4 tons?

Chemistry
1 answer:
zloy xaker [14]4 years ago
6 0
Do you want the estimated answer or the exact answer?

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What volume will 0.875 moles of kr occupy at stp?
Hunter-Best [27]
1 mole --------- 22.4 L at ( STP )
0.875 moles ----- ?

0.875 x 22.4 / 1 => 19.6 L

hope this helps!
7 0
4 years ago
Read 2 more answers
What is one of the ways a fission reaction can get out of control? when there are too many neutrons when the neutrons are slowed
Juliette [100K]

Out of the following given choices;

A) when there are too many neutrons

B) when the neutrons are slowed down

C) when there is a chain reaction

D) when there is critical mass

The answer is A. A fission nuclear reactor is controlled by regulating the number of neurotoxins produced in the chain reaction. Too many neutrons cause an accelerated chain reaction that causes enormous heat to be generated in a short amount of time which could cause an explosion. Control rods , made of “neutron poisons”, e.g. cadmium, are put in the reactors to control the number of neutrons at any one time

6 0
3 years ago
Which statement about the sun's energy is correct?
vagabundo [1.1K]

Answer:

C. A part of it is absorbed by atmospheric gases.

Explanation:

brainiest plz

3 0
3 years ago
Read 2 more answers
So you are using the combined gas law
shusha [124]

Answer:

7.22L

Explanation:

At Stp T2 = 273K and P2 is 1 atm

So we have the following data

V1 =10L. P1=650mmHg(0.855atm)

V2 =V2. P2 = 1 atm

T1=50°c (323K) T2 =273K

Hence from the combined gas law

P1xV1 /T1 =P2xV2/T2

0.855x10/323 =1xV2 /273

8.55/323 =V2 /273

V2 = 8.55x273 /323

V2 = 7.226 L

5 0
3 years ago
A gas tank holds 285 L of propane, C3H8, at 530. mm Hg. What is the volume of the propane at standard pressure? A)408.7L B)408.7
Mashcka [7]

Answer:

option D

Explanation:

Given,

V₁ = 285 L

P₁ = 530 mm Hg

Standard pressure

P₂ = 760 mm Hg

V₂ = ?

Using relation between pressure and volume

\dfrac{P_1}{V_2}=\dfrac{P_2}{V_1}

\dfrac{530}{V_2}=\dfrac{760}{285}

V_2 = 198.75\ L

Hence, volume of the propane at standard pressure is equal to 198.8 L.

Hence, the correct answer is option D.

5 0
3 years ago
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