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gayaneshka [121]
3 years ago
3

Consider two bicycle riders, A and B. The two riders have equal masses Mrider A = Mrider B and their respective bicycles also ha

ve similar frames, Mframe A = Mframe B . Finally, the wheels of the two bicycles have equal masses Mwheel A = Mwheel B and equal radii R wheel A = R wheel B but different mass distributions: the wheels of bike A have most of their masses at the rims, Wheel A, while the wheels of bike B have their masses ‘spread’ evenly over the whole wheel area, Wheel B. The two cyclists travel at the same speed on level ground. They approach a low hill and decide to coast up instead of hard pedalling. At the top of the hill, which of the two bikes will have a larger speed? Assume no friction nor air resistance, and all the wheels roll on the ground without slipping.
Physics
1 answer:
Allisa [31]3 years ago
6 0

bika B.

because moment of inertia is lower in bike B.

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4 years ago
While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.
lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

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Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

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Answer:

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Quantitative research is defined as a systematic investigation of phenomena by gathering quantifiable data and performing statistical, mathematical, or computational techniques.

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3 years ago
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