Answer:
Mal = 0.232 kg = 232 g
Explanation:
mass of water (Mw) = 225 g = 0.225 kg
mass of copper stirrer (Mcu) = 40 g = 0.04 kg
initial temperature of water (Tw) = 27 degrees
mass of silver (Mag) = 470 g = 0.47 kg
initial temperature of silver (Ts) = 85 degrees
final temperature of the mixture (T) = 32 degrees
find the mass of the aluminum cup (Mal)
applying the conservation of energy
((Mal.cAl) + (Mw.cW) + (Mcu.cCu))(ΔTw) = (Mag.cAg)(ΔTag)
we require the specific heat capacities of water (cW) , aluminium (cAl) , copper (cCu) and silver (cAg) which are as follows
water (cW) =4186 J/kg.K
aluminium (cAl) = 900 J/kg.K
copper (cCu) = 387 J/kg.K
silver (cAg) = 234 J/kg.K
now we can put in our values to get the mass of the Aluminium cup (Mag)
((Mal.900) + (0.225 x 4186) + (0.04 x 387))(32-27) = (0.47 x 234)(85-32)
(900 . Mal + 957.33) x 5 = 5828.94
900 .Mal + 957.33 = 1165.79
900.Mal = 1165.79 - 957.33 = 208.5
Mal = 0.232 kg = 232 g
